Maths, Addmaths and Statistics: Post your doubts here!

[peacce]

d)Compare this sequence with above pattern of R,you will see every value of R is 3 times that of this patter e.g 3 in R 1 in this pattern so multiply it be 3 to get 3/2 (n(n+1)

e)Put 15 in the above sequence and evaluate.

f)1/2 (N+1)(N+2) I kinda remember this pattern from Past papers.You can also compare and deduce these complex patterns,notice that in D each value is one number ahead of the above pattern given e.g 1,3,6,10 in given pattern and 3,6,10,15 in D so we will add (n+1)(since each number is of the next n) to the equation.

m nt gttng u man
a part mei 3 times kaha hai.. diff ratio hai har bar
B part mei 15 put krk 120 ans ara ms mein 360 hai
Part f tu sir se guzr

 

[peacce]

d)Compare this sequence with above pattern of R,you will see every value of R is 3 times that of this patter e.g 3 in R 1 in this pattern so multiply it be 3 to get 3/2 (n(n+1)

e)Put 15 in the above sequence and evaluate.

f)1/2 (N+1)(N+2) I kinda remember this pattern from Past papers.You can also compare and deduce these complex patterns,notice that in D each value is one number ahead of the above pattern given e.g 1,3,6,10 in given pattern and 3,6,10,15 in D so we will add (n+1)(since each number is of the next n) to the equation.

m nt gttng u man
a part mei 3 times kaha hai.. diff ratio hai har bar
B part mei 15 put krk 120 ans ara ms mein 360 hai
Part f tu sir se guzr

 

[Muhammad_Hamza]

a)Total area is 138.Since it has one line of symmetry other side will have half area of 69(EFAB).Then apply trapezium formula 1/2 x 6 x (16 +AF)

b)i)Divide total area by 4 to get 34.5.Then apply triangle area and solve it (1/2 x 12 x EG )

ii)Find EG and then minus it from 16 to get GB.Divide them on your calc and get ratio of 23:41

http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_s13_qp_22.pdf
Q6- Please.. bearing aaj tk samaj nae aya........plz

 

[peacce]

d)Compare this sequence with above pattern of R,you will see every value of R is 3 times that of this patter e.g 3 in R 1 in this pattern so multiply it be 3 to get 3/2 (n(n+1)

e)Put 15 in the above sequence and evaluate.

f)1/2 (N+1)(N+2) I kinda remember this pattern from Past papers.You can also compare and deduce these complex patterns,notice that in D each value is one number ahead of the above pattern given e.g 1,3,6,10 in given pattern and 3,6,10,15 in D so we will add (n+1)(since each number is of the next n) to the equation.

m nt gttng u man
a part mei 3 times kaha hai.. diff ratio hai har bar
B part mei 15 put krk 120 ans ara ms mein 360 hai
Part f tu sir se guzr

 

[peacce]

d)Compare this sequence with above pattern of R,you will see every value of R is 3 times that of this patter e.g 3 in R 1 in this pattern so multiply it be 3 to get 3/2 (n(n+1)

e)Put 15 in the above sequence and evaluate.

f)1/2 (N+1)(N+2) I kinda remember this pattern from Past papers.You can also compare and deduce these complex patterns,notice that in D each value is one number ahead of the above pattern given e.g 1,3,6,10 in given pattern and 3,6,10,15 in D so we will add (n+1)(since each number is of the next n) to the equation.

m nt gttng u man
a part mei 3 times kaha hai.. diff ratio hai har bar
B part mei 15 put krk 120 ans ara ms mein 360 hai
Part f tu sir se guzr

 

[peacce]

d)Compare this sequence with above pattern of R,you will see every value of R is 3 times that of this patter e.g 3 in R 1 in this pattern so multiply it be 3 to get 3/2 (n(n+1)

e)Put 15 in the above sequence and evaluate.

f)1/2 (N+1)(N+2) I kinda remember this pattern from Past papers.You can also compare and deduce these complex patterns,notice that in D each value is one number ahead of the above pattern given e.g 1,3,6,10 in given pattern and 3,6,10,15 in D so we will add (n+1)(since each number is of the next n) to the equation.

m nt gttng u man
a part mei 3 times kaha hai.. diff ratio hai har bar
B part mei 15 put krk 120 ans ara ms mein 360 hai
Part f tu sir se guzr

 

[asadalam]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s13_qp_22.pdf
Q6- Please.. bearing aaj tk samaj nae aya........plz

Which part....

 

[M.Omar]

Solving it. Part b is the real deal right?

Yup.

 

[asadalam]

m nt gttng u man
a part mei 3 times kaha hai.. diff ratio hai har bar
B part mei 15 put krk 120 ans ara ms mein 360 hai
Part f tu sir se guzr

I cant explain more clearer than that.These things are best learnt and understood via teachers.

 

[princess Anu]

?

 

[Muhammad_Hamza]

Which part....

Pura Question

 

[asadalam]

Pura Question

...acha chalo theek hai...

a)Both norths are parallel and 65 would become the alternate angle.210-180=30 and 30 out of those 65 alterntate angle will be subtracted to get angle of 35.
b)Drop perpendicular from P to QR and apply sin 35=x/500 and solve.

c)Find SPQ by applying tan inverse of 335/500.Then subtract that from 65 to get the bearing.

Get it?

 

[peacce]

I cant explain more clearer than that.These things are best learnt and understood via teachers.

 

[Muhammad_Hamza]

...acha chalo theek hai...

a)Both norths are parallel and 65 would become the alternate angle.210-180=30 and 30 out of those 65 alterntate angle will be subtracted to get angle of 35.
b)Drop perpendicular from P to QR and apply sin 35=x/500 and solve.

c)Find SPQ by applying tan inverse of 335/500.Then subtract that from 65 to get the bearing.

Get it?

G bilkul thanks g

 

[peacce]

d)Compare this sequence with above pattern of R,you will see every value of R is 3 times that of this patter e.g 3 in R 1 in this pattern so multiply it be 3 to get 3/2 (n(n+1)

e)Put 15 in the above sequence and evaluate.

f)1/2 (N+1)(N+2) I kinda remember this pattern from Past papers.You can also compare and deduce these complex patterns,notice that in D each value is one number ahead of the above pattern given e.g 1,3,6,10 in given pattern and 3,6,10,15 in D so we will add (n+1)(since each number is of the next n) to the equation.

part d umean they r multiples of 3 right?

 

[exploded diper]

Yup.

do u know the answer

 

[Ram97]

part d umean they r multiples of 3 right?

for part d apply this formula
first term + (n-1)(first difference) + (n-1)(n-1)(second difference/2)

 

[asadalam]

part d umean they r multiples of 3 right?

No i mean they are 3 times bigger than the numbers in the sequence that have been given to you. i.e 3 is 3 times bigger than 1 ,9 is 3 times bigger than 3 , 18 is 3x than 6.You have to compare them in complex sequences.

 

[M.Omar]

do u know the answer

yes.

 

[Kamihus]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s13_qp_22.pdf
q 2 d,e( y 360?),f ??

There are formulas for this and I remember doing this question by those formulas in my finals.