Maths, Addmaths and Statistics: Post your doubts here!

[asadalam]

u have to...p.s u would not be able to resist the temptation to check the site so u could see what other ppl had done in their paper....

I'll not come home till dopahar at least so i cant check it even if i wanted to...maybe in evening

nabeel kon hai?

Dark Destination

 

[asadalam]

Kid's got plans. :3

awaragardi

 

[exploded diper]

I'll not come home till dopahar at least so i cant check it even if i wanted to...maybe in evening

Dark Destination

cool stuff

 

[exploded diper]

awaragardi

yar teri bili nay kya helmet pani hui hay?

 

[asadalam]

Alright - I am incredibly illprepared at the moment.

Which topics have had the toughest questions in all the past papers?

asadalam
***amd***
Dark Destination
@whoeverelse

Proving congruency is sometimes hard,mensuration qs are usually hard...others are also sometimes difficult qs like in vectors,transformation,number sequence.

yar teri bili nay kya helmet pani hui hay?

Astronaut hai =3

 

[exploded diper]

Proving congruency is sometimes hard,mensuration qs are usually hard...others are also sometimes difficult qs like in vectors,transformation,number sequence.

Astronaut hai =3

thought so.....

 

[Dream.Eater]

QB anyone???????

 

[asadalam]

View attachment 44120

QB anyone???????

 

[asadalam]

You have saved that image?

Browser history bhi ek chees hoti hai =P

 

[exploded diper]

so if a question like this comes in exam .......can we explain our theories or working like this......

 

[exploded diper]

Browser history bhi ek chees hoti hai =P

is sey to behtar tha save hi kar li hoti.....

 

[asadalam]

How to prove?

 

[Dream.Eater]

How to prove?View attachment 44121

Easy..
A and D are midpoints of OB and OC therefore OA=OD =6
AOD = 60 and since OA =OD base angles are also 60 ((180-60)/2)
Thus it is equilateral so AD =6

 

[funky brat]

How to prove?View attachment 44121

AO and OD are 6 too, since they are midpoints. AOD is 60 so 180-60= 120
120/2= 60.
Since all angles equal all sides must be equal too hence AD= 6cm.

 

[Mahnoorfatima]

http://papers.xtremepapers.com/CIE/...(Calculator Version) (4024)/4024_w06_qp_2.pdf
In the last question, 11, last part , e, why do we need to multiply the probability by two when we're already selecting 2 students only?

 

[asadalam]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w06_qp_2.pdf
In the last question, 11, last part , e, why do we need to multiply the probability by two when we're already selecting 2 students only?

There is no order given thus we will multiply by 2.

More clearly
Student higher than 170 = A
Student lower than 140=B

One probability is A x B (A chosen then B) and other is B x A(B chosen then A)Since both are AB we will add their probabilities and it will seem that we have multiplied by 2,while we have just added the 2 orders.

 

[exploded diper]

My way is kind of long.

Since they are midpoints, 6 cm is the length of AO and DO. Use that and cos 60 in your cosine rule to figure out AD. AD^2 = DO^2 + AO^2 - 2(DO)(AO)(cos 60)

thts the method i used too....

 

[asadalam]

Ans plis

 

[exploded diper]

Ans plisView attachment 44122

apcb is a quadilateral and thus through the property opposite angles in a cyclic quad.....abc +apc=180 so 180 -90=90....








getting me?

 

[asadalam]

apcb is a quadilateral and thus through the property opposite angles in a cyclic quad.....abc +apc=180 so 180 -90=90....








getting me?

Yup,thanks but the ms stated b) (i) Angle in a semicircle oe thats why i was confused.