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MATHS P12

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Talha said:
the equation was 4√x + x... M was da maximam point.... now tel me how u got m as (4,4)
if i'm not wrong the question wasn't 4√x + x instead it was this 4√x - x...tht gives the answer (4,4)
 
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I got -1 to 6.81 do you think they'll give me a mark for getting -1 right?
 
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ibrahimovais said:
aaakhtar19 said:
these r my answers anyone having contradiction please discusss
thnx
i think the range is -1 t0 7

the range in a part was -1 to 3 (y=3-4cos^2 x)
but in the graph, it was -1 to 7 (y=3-4cos x)
because both had different equations.
 
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sasukeuchiha said:
ibrahimovais said:
aaakhtar19 said:
these r my answers anyone having contradiction please discusss
thnx
i think the range is -1 t0 7

the range in a part was -1 to 3 (y=3-4cos^2 x)
but in the graph, it was -1 to 7 (y=3-4cos x)
because both had different equations.

how abt the vector angle part man can we take the angle frm BA BC and frm AB CB
 
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For all whose range was -1 to 7
Range of cosx= -1 to 1
therefore range of cos^2 x...would be 0 to 1...because sqr of 1 and -1 would be 1...then the least value wud be 0
now....if u put 1 and 0 in 3-4cos^2 x,,,,,you'll get....-1 to 3
got it!!! :)
 
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inshAllah let the threshold go down cuz all the ppl in my centre were sooo upset nd the paper was horibble too dint get some answers paper was tough nd tricky :( inshAllah mechanics will be good
 
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got only coordinates of M wrong... InshAllah hoping for 70+ !!!
 
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For Q6, the angle between the tangent and the x-axis, I got the obtuse angle instead of the acute one (the question didn't state it needed the acute). Would I get the mark ?
 
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ANY1 REMEMBER THE VECTORS "OA, OB, & OC" OF THE VECTOR QUESTION????? PLEASE DO TELL ME!!! :cry:
 
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I got the angle of the sector wrong so i got the perimeter 15.6 cm. will i get any marks for the method?????
 
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why not...u'll get marks for ur correct method cuz of EFC (error carried forward) :)
 
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