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Since 24 hours are almost up, I'm re-opening this topic.
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THANKSMAVtKnmJ said:Since 24 hours are almost up, I'm re-opening this topic.
ks136 said:So this is what i remember
Q. prove that cosx/tanx(1-sinx) = 1 +1/sinx
Q.fx= 3-4cos^k x
(a)when k=2...state the range of fx...my ans was -1<f<3
i dont remember its b part
(ii) when k=1
(a) sketch the graph
Q:A circle is divided into sectors..in a way that there anglees form A.P...
the angle of largest sector is four times greater than the smallest one....radius is 5 cm....what is the perimeter of smallest sector
.....My answer...angle of smallest one is 24...p=12.1
farhan29 said:ks136 said:So this is what i remember
Q. prove that cosx/tanx(1-sinx) = 1 +1/sinx
Q.fx= 3-4cos^k x
(a)when k=2...state the range of fx...my ans was -1<f<3
i dont remember its b part
(ii) when k=1
(a) sketch the graph
Q:A circle is divided into sectors..in a way that there anglees form A.P...
the angle of largest sector is four times greater than the smallest one....radius is 5 cm....what is the perimeter of smallest sector
.....My answer...angle of smallest one is 24...p=12.1
range was -1<f(x)<7
Q b was to solve the equation
it was (8i+1J+8k)sniper7137 said:Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.
But does anyone know what the vector OD was?
sorrysniper7137 said:Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.
But does anyone know what the vector OD was?
farhan29 said:it was (8i+1J+8k)sniper7137 said:Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.
But does anyone know what the vector OD was?
intel1993 said:mashallah paper went very gud...........
Range was -1<f(x)<3 and angle of tange with x axis was 71.6 degrees..............volume in the last question was 136.5pi..........
perimeter in the q10 was 12.09 ....................and the smallest angle was 24 degre.........
value of p and q in q2 were -2 and -15
and vector was achieved by the vector move method i dont remeber the exact cordinates but it sumething involving 8 and 1 ...............
farhan29 said:yes my bad ..the range was -1<f(x)<3 i think i got it wrong...1 mark ryt?
how did u attempted dat???sniper7137 said:Yes Yes Yes :Bravo: :Bravo: :Bravo: Those are the exact coordinates of OD vector (8i + 1j + 8k). And the logic behind it was absurdly simple now that i think of it.
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