MATHS P12

[MAVtKnmJ]

Since 24 hours are almost up, I'm re-opening this topic.

 

[ks136]

Since 24 hours are almost up, I'm re-opening this topic.

THANKS

 

[ks136]

So this is what i remember
Q. prove that cosx/tanx(1-sinx) = 1 +1/sinx
Q.fx= 3-4cos^k x
(a)when k=2...state the range of fx...my ans was -1<f<3
i dont remember its b part
(ii) when k=1
(a) sketch the graph

Q:A circle is divided into sectors..in a way that there anglees form A.P...
the angle of largest sector is four times greater than the smallest one....radius is 5 cm....what is the perimeter of smallest sector
.....My answer...angle of smallest one is 24...p=12.1

 

[farhan29]

So this is what i remember
Q. prove that cosx/tanx(1-sinx) = 1 +1/sinx
Q.fx= 3-4cos^k x
(a)when k=2...state the range of fx...my ans was -1<f<3
i dont remember its b part
(ii) when k=1
(a) sketch the graph

Q:A circle is divided into sectors..in a way that there anglees form A.P...
the angle of largest sector is four times greater than the smallest one....radius is 5 cm....what is the perimeter of smallest sector
.....My answer...angle of smallest one is 24...p=12.1

range was -1<f(x)<7
Q b was to solve the equation

 

[ks136]

So this is what i remember
Q. prove that cosx/tanx(1-sinx) = 1 +1/sinx
Q.fx= 3-4cos^k x
(a)when k=2...state the range of fx...my ans was -1<f<3
i dont remember its b part
(ii) when k=1
(a) sketch the graph

Q:A circle is divided into sectors..in a way that there anglees form A.P...
the angle of largest sector is four times greater than the smallest one....radius is 5 cm....what is the perimeter of smallest sector
.....My answer...angle of smallest one is 24...p=12.1

range was -1<f(x)<7
Q b was to solve the equation

NO....WE DISCUSSED THIS YESTERDAY....IT WAS -1 TO 3....U DID IT WRONG....

 

[ks136]

AND for the question in which it asked for what angle does the tangent makes with the x axis ...my ans was71.6 degrees

 

[sniper7137]

Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.

But does anyone know what the vector OD was?

 

[farhan29]

ok..maybe. But in dhaka almost everyone got -1<f(x)<7 since de least value of 4cos^2x is -4 so 3-(-4) = 7 which is de max value ..thats how i did it and most of my friends did maybe we are wrong ..you would know better

 

[farhan29]

Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.

But does anyone know what the vector OD was?

it was (8i+1J+8k)

 

[ks136]

Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.

But does anyone know what the vector OD was?

sorry

 

[ks136]

Yes!!! All my answers are matching: 24 degrees smallest sector angle, 12.1 cm perimeter, 71.6 degrees tangent angle, -1 <= f(x) <= 3 range.

But does anyone know what the vector OD was?

it was (8i+1J+8k)

right..i remember now....

 

[intel1993]

mashallah paper went very gud...........
Range was -1<f(x)<3 and angle of tange with x axis was 71.6 degrees..............volume in the last question was 136.5pi..........
perimeter in the q10 was 12.09 ....................and the smallest angle was 24 degre.........
value of p and q in q2 were -2 and -15
and vector was achieved by the vector move method i dont remeber the exact cordinates but it sumething involving 8 and 1 ...............

 

[ks136]

mashallah paper went very gud...........
Range was -1<f(x)<3 and angle of tange with x axis was 71.6 degrees..............volume in the last question was 136.5pi..........
perimeter in the q10 was 12.09 ....................and the smallest angle was 24 degre.........
value of p and q in q2 were -2 and -15
and vector was achieved by the vector move method i dont remeber the exact cordinates but it sumething involving 8 and 1 ...............

right... my all answers match

 

[farhan29]

yes my bad ..the range was -1<f(x)<3 i think i got it wrong...1 mark ryt?

 

[ks136]

yes my bad ..the range was -1<f(x)<3 i think i got it wrong...1 mark ryt?

2 marks 1 think so...or may be 1

 

[sniper7137]

Yes Yes Yes :Bravo: :Bravo: :Bravo: Those are the exact coordinates of OD vector (8i + 1j + 8k). And the logic behind it was absurdly simple now that i think of it.

 

[ks136]

Yes Yes Yes :Bravo: :Bravo: :Bravo: Those are the exact coordinates of OD vector (8i + 1j + 8k). And the logic behind it was absurdly simple now that i think of it.

how did u attempted dat???

 

[aaakhtar19]

these r my answers anyone having contradiction please discusss
thnx

 

[ks136]

HEY I THINK MINE R SAME.........I THINK THAT U MIGHT GET FULL MARKS....I DIDNT INCLUDED C in 1st Q...How many marks will be deducted?

 

[intel1993]

hey my ans r also correct...........yea.............>>>>