it's pentagon
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MATHS PAPER 22 / JUNE 2012?
- Thread starter ROCK THE FIRST
- Start date
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Yeah i guess we were told to do it that way give ur answers as simplified as possible it said
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REALLY !
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no in vectors da qs didnt said to give da ratio in simplified form i read it 3 times
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Ratios are always given in integers. like 1:2 , 3:4, 4:5.
In Q question8 of paper2 were we had to find area of major segment
Us k aglay part main us k neechay aik trapezium attach kia tha
(dnt tell me u dnt knkw difference in a trapezium and a parallelogram)
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Yes it was a trapezium 100% sure some people dont even remember the shapes correctly kitna khail te hai woh log
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no da qs was f 1 mark n da main aim f da qs was to find da ratio ......n it was up to u how u rite da ratio .....in decimals,fractions or integers...n da qs didnt also told to simplify ...!!!
Aik mark k liay itna koun ro rahay ho
Apne jo kia sai kia ab bas karo
- Messages
- 4,162
- Reaction score
- 1,119
- Points
- 173
DUDE preceeding the parts it had already said give ur answers simplified and even if this wasnt said ratios are never given in decimals they are given in integers although ur answer may be accepted if they wish to keep praying and hope for the best only thing we can do now
- Messages
- 4,162
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- 1,119
- Points
- 173
- Messages
- 4,162
- Reaction score
- 1,119
- Points
- 173
THATS like asking someone what did u eat 1 month ago !
thAT QUES WAS TRIGONOMETRY so there were too many lengths to remember i dont know but pehlay walay mein u needed to use Cosine rule to find the angle then Sine rule and a basic trig ratio after that i cant think
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hey guys in finding the area of shape 2 u shud use the similar triangle method or jst calculate it!!!!!!!
similar triangle method... and u should get something 37...
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THATS like asking someone what did u eat 1 month ago !
thAT QUES WAS TRIGONOMETRY so there were too many lengths to remember i dont know but pehlay walay mein u needed to use Cosine rule to find the angle then Sine rule and a basic trig ratio after that i cant think
Chah Gaye sir jee!
that's exactly what i used!! I actually first assumed that that angle was 45 and the line was bisecting that 90 degree angle .. LOL but I corrected it later .. my cosine rule part had a lot of cutting in it
I hope that it doesn't get me in trouble!
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hey!! did any one do the last question in section B that graph question??
me too! for the first try. I assumed that it was 45 degree because the square was bisected! haha. Then I realised that you can find AD by two waysChah Gaye sir jee!
that's exactly what i used!! I actually first assumed that that angle was 45 and the line was bisecting that 90 degree angle .. LOL but I corrected it later .. my cosine rule part had a lot of cutting in it
(i) the value of angle ABC - 90 ---> use sine + 2
(ii) 360 -180 - value of angle ABC ----> use cosine + 2
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I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph