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MATHS PAPER 22 / JUNE 2012?

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I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph :(

The best thing is never do graphs until in need of it badly :) which ques did u leave for doin this graph question !
 
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The best thing is never do graphs until in need of it badly :) which ques did u leave for doin this graph question !

Angle Properties of circle, I wasn't sure about two of my answers .. so I thought screw it .. let's do the last question as it had mensuration in it .. and mensuration is like my favourite topic :D
 
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Scale factor was 2. right?

3k^2=12
k^2=4
k=2
No..
you do not have to put square on K in this case because it was a single stretch. the formula was: Area of Image= K * (Area of Original figure)
Whereas the one you applied is of double stretch or enlargement.

Solution:
Area of original figure(Triangle)=3
Area of Image(stretched triangle)=12

Area of Image= K * (Area of Original figure)
12 = K *3
K=12/3
K=4
 
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What about the circle's answers? And the bisector angle plus the other angle in parallelogram with reason?
 
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I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph :(
I don't think so it was written estimate the the value, I too got 4.8 but then i estimated it to 5 and wrote 5 in the answer space.
 
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Can any one tell me what was the height of the cuboid in last question of section b(Q 12). we had to read it from graph.
 
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yes, what did you wrote in the height of the cuboid part of that question. I got 4.6 from my graph and then I subtracted it from 8 and got 3.4. h=8-x, wasn't it like that.

I think my value from the graph was 4.2 and when i subtracted it from 8 i got 3.8 as my answer...

and what was the last questions' answer??

my equation was coming 27x and the final answer was 5.
 
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I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph :(
The value of the graph should have been 4.6. I used the equation to calculate and if you used 4.6, area was coming to 120.37, if you used 4.5 it was coming to 116, and 124 for 4.5.
 
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THATS like asking someone what did u eat 1 month ago !
thAT QUES WAS TRIGONOMETRY so there were too many lengths to remember i dont know but pehlay walay mein u needed to use Cosine rule to find the angle then Sine rule and a basic trig ratio after that i cant think :D
It was 21.3
 
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Chah Gaye sir jee!

that's exactly what i used!! I actually first assumed that that angle was 45 and the line was bisecting that 90 degree angle .. LOL but I corrected it later .. my cosine rule part had a lot of cutting in it :D I hope that it doesn't get me in trouble!

i assumed the angle 45 and still got the right angle by applying the sine rule which was 128 degrees!! i Guess !!
 
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