MATHS PAPER 22 / JUNE 2012?

[scouserlfc]

I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph

The best thing is never do graphs until in need of it badly which ques did u leave for doin this graph question !

 

[syed1995]

The best thing is never do graphs until in need of it badly which ques did u leave for doin this graph question !

Angle Properties of circle, I wasn't sure about two of my answers .. so I thought screw it .. let's do the last question as it had mensuration in it .. and mensuration is like my favourite topic

 

[COMMUNICATER]

can u tel me da area whch was given in da qs no 8 f menstruation in whch we had to find da height....n also da value f parallel side

it's mensuration not menstruation `

 

[asd]

it's mensuration not menstruation `

LMAOO!!

 

[muhammadrafay]

Can anyone tell me the answer of the scale factor and (m,n)

M=1 and N=4

 

[muhammadrafay]

i dont remember maybe i put 7/20

0.6a-0.35b-c

 

[pakisatan123]

did any one gt x value on second page =0.6

 

[muhammadrafay]

Scale factor was 2. right?

3k^2=12
k^2=4
k=2

No..
you do not have to put square on K in this case because it was a single stretch. the formula was: Area of Image= K * (Area of Original figure)
Whereas the one you applied is of double stretch or enlargement.

Solution:
Area of original figure(Triangle)=3
Area of Image(stretched triangle)=12

Area of Image= K * (Area of Original figure)
12 = K *3
K=12/3
K=4

 

[muhammadrafay]

can i answer the vectors in factorised form? for example 2/5(a-b)

yes

 

[muhammadrafay]

Wat was da answer to the first qs f da paper2....in whch he was askin us to identify da shape..!!!

Pentagon

 

[bikermicefrmars]

What about the circle's answers? And the bisector angle plus the other angle in parallelogram with reason?

 

[muhammadrafay]

hey!! did any one do the last question in section B that graph question??

yes, what did you wrote in the height of the cuboid part of that question. I got 4.6 from my graph and then I subtracted it from 8 and got 3.4. h=8-x, wasn't it like that.

 

[muhammadrafay]

I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph

I don't think so it was written estimate the the value, I too got 4.8 but then i estimated it to 5 and wrote 5 in the answer space.

 

[Doosh Bag]

7/20(xxxxxx)

7b/20 is correct

 

[muhammadrafay]

Can any one tell me what was the height of the cuboid in last question of section b(Q 12). we had to read it from graph.

 

[Doosh Bag]

In the major sector question, was the very last answer of the question, 7.57 ?

 

[syed1995]

yes, what did you wrote in the height of the cuboid part of that question. I got 4.6 from my graph and then I subtracted it from 8 and got 3.4. h=8-x, wasn't it like that.

I think my value from the graph was 4.2 and when i subtracted it from 8 i got 3.8 as my answer...

and what was the last questions' answer??

my equation was coming 27x and the final answer was 5.

 

[perfect1]

I did .. my last question answer was coming 5 .. although some of my friends got 4.8 as their answer .. but my curve was not at all smooth! I will lose 2 marks in the construction of that graph

The value of the graph should have been 4.6. I used the equation to calculate and if you used 4.6, area was coming to 120.37, if you used 4.5 it was coming to 116, and 124 for 4.5.

 

[perfect1]

THATS like asking someone what did u eat 1 month ago !
thAT QUES WAS TRIGONOMETRY so there were too many lengths to remember i dont know but pehlay walay mein u needed to use Cosine rule to find the angle then Sine rule and a basic trig ratio after that i cant think

It was 21.3

 

[beeloooo]

Chah Gaye sir jee!

that's exactly what i used!! I actually first assumed that that angle was 45 and the line was bisecting that 90 degree angle .. LOL but I corrected it later .. my cosine rule part had a lot of cutting in it I hope that it doesn't get me in trouble!

i assumed the angle 45 and still got the right angle by applying the sine rule which was 128 degrees!! i Guess !!