- Messages
- 204
- Reaction score
- 455
- Points
- 53
What'd you have to find in part 1?
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
D - R = maYupp.
See the mass of the car was 600kg and the acceleration was 1.4 and the Power given to you was 22.5 kW. and v=18
A car of mass 600 kg is travelling along a horizontal road where the resistance to motion is constant and equal to R. The acceleration is 1.4 at a point when the power of the engine is 22.5kW and the speed of the car is 18/ Find RWhat'd you have to find in part 1?
no worries. Still you get marks for the correct method,.D - R = ma
=> D = R + ma
=> R = D - ma
=> R = P/v - ma
Blah blah... right?
And then you substitute that into something else and wala! You get the answer.
I guess I typed something wrong in the calculator then. -___-
cheer upSigh. :\
Hell naw.cheer up
you still have a chance at an A*. If you're chances go, then what about me? I made a lot of mistakes in Q5?Hell naw.
There goes my chances of getting an A*.
I made stupid mistakes all throughout the damn paper. :\you still have a chance at an A*. If you're chances go, then what about me? I made a lot of mistakes in Q5?
The 5kg one was resting on the slope. The 16 kg one was hanging from the pulley.I made stupid mistakes all throughout the damn paper. :\
And d'you remember the values for the masses of the particles in #5?
You, sir, have a strong memory.The 5kg one was resting on the slope. The 16 kg one was hanging from the pulley.
hahaaha. Hyper memory syndrome lol.You, sir, have a strong memory.
Okay, well, lemme write up all the solutions, okay? And then I'll post it on here.
What was the coefficient of friction?hahaaha. Hyper memory syndrome lol.
And yayyyyy thanks.
1/ (sqrt(3))What was the coefficient of friction?
awesome thankssssssssss
Will you be posting other solutions as well?
InshaaAllahWill you be posting other solutions as well?
Is there ECF in m1?P was 6150W
because at constant speed the forward force will be equal to the resistive force. So using P =FV, where F=410 and v=15
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now