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paper 12 chemistry ...

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whtz da ans for nitrogen yield one question????????whox enthalpy is -92kj...i go wid 'C : increasing the pressure" will increase the yield!!!!!!!!!plzzzzzz tel me m i ryt?????????????? PLZZZ
 
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whtz da ans for nitrogen yield one question????????whox enthalpy is -92kj...i go wid 'C : increasing the pressure" will increase the yield!!!!!!!!!plzzzzzz tel me m i ryt?????????????? PLZZZ
 
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whtz da ans for nitrogen yield one question????????whox enthalpy is -92kj...i go wid 'C : increasing the pressure" will increase the yield!!!!!!!!!plzzzzzz tel me m i ryt?????????????? PLZZZ
Yep u are right and calm down :p
 
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sorry my mistake it was CH3+ confirm and options were BeCl3 CH3+ and AlCl3 both BeCl3 and AlCl3 have trigonal planer shape and as there is one electron missing in CH3+ it will also have planer shape in this state.
We are talking p12 right? The 1st question was which of the underlined elements has an incomplete outer shell electron?
A. BF3 (B was underlined i think)
B. CH3 (+ or - i cant recall)
C Sth
D. H3O+
 
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We are talking p12 right? The 1st question was which of the underlined elements has an incomplete outer shell electron?
A. BF3 (B was underlined i think)
B. CH3 (+ or - i cant recall)
C Sth
D. H3O+
hahaha i was then talking about 31st or 32nd mcq and yeah same paper here..:p
 
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i dont think it was the first question because first was the graph question of decreasing temp.
it would be 4 or 5th question on the second page. my ans to 4 was B and 5 was A.
 
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We are talking p12 right? The 1st question was which of the underlined elements has an incomplete outer shell electron?
A. BF3 (B was underlined i think)
B. CH3 (+ or - i cant recall)
C Sth
D. H3O+
if this is the question then answer should be A and CH3 had -ve charge.
it was the question above that one about pressure.
 
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In paper 12 they said which of them has a single unpaired electron in their outer shell...the options were almost the same...one was only different and tht was a free radical..
 
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Im sure that the options which contained the product alkane was incorrect..alkenes dont produce alkanes when cracked. i went for D as W and X only because Z had too double bonds..
The Cracking One was a simple question. The Answer was W X Z.
Cracking of Alkane Produces: Alkanes (Same as Reactant) + Alkene (Addition Of a Double Bond to the reactant molecule)
Cracking Of Alkene Produces : Alkene (Same as Reactant) + DiAlkene ( Addition of A Double Bond to the reactant molecule)
In the case given in the paper it was an alkene, so the answer was W X Z.
 
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Would anyone please tell the answer to the Hemlock question. Was it B? If it wasn't, then why?? :|
 
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The Cracking One was a simple question. The Answer was W X Z.
Cracking of Alkane Produces: Alkanes (Same as Reactant) + Alkene (Addition Of a Double Bond to the reactant molecule)
Cracking Of Alkene Produces : Alkene (Same as Reactant) + DiAlkene ( Addition of A Double Bond to the reactant molecule)
In the case given in the paper it was an alkene, so the answer was W X Z.
Man but still in the question they wrote are produced TOGETHER doesnt that mean all the C's and H's cant be more than the alkene being cracked?
 
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