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Paper 5 Tips !! :)

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Alright, underline your kewords as you read the question.. tell me what you're gonna label your columns..i'll guide you inshAllah.

i labelled my coloums as

mass of water/gm (C-B)
mass of solid/gm (E-D)
and i calculated solubilty by diving (E-D)/(C-B) i.e F/E.
Did i did correct? Thank you.
 
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i labelled my coloums as

mass of water/gm (C-B)
mass of solid/gm (E-D)
and i calculated solubilty by diving (E-D)/(C-B) i.e F/E.
Did i did correct? Thank you.
Yea, you calculated the mass of the solid and that of water correct. But the solubility would be grams of solid/ 100g of water.
 
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Yea, you calculated the mass of the solid and that of water correct. But the solubility would be grams of solid/ 100g of water.

yeah! for example i calculated the mass of solid 2.0 gm, so wouldn't my solubility would be mass of solid( 2gm)/mass of water(which i calculated using C-B) or it would be mass of solid/100
 
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In o/n 2008 paper ...question 1 :

the solubility is given as mass of solid/ mass of water x 100 ............does that mean mass of solid crystallised or undissolved??
 
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v3 i think...it's l8..i'm actually very sleepy..spent my life's energy on p5 the whole day;)
v.53 is about moles ratio ....very easy ...........calculate mass of lead (C-A) ....then mass of oxygen(C-B) ....the other columns ...get the no. of moles by diving each mass by Ar of the element ....plot a graph of moles of lead against moles of oxygen ,...the slope give u a ratio hence the formula of the compound :)
 
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