Can any one plz help me with this 2nd q of w12 53 http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w12_qp_53.pdf
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Alright, underline your kewords as you read the question.. tell me what you're gonna label your columns..i'll guide you inshAllah.
with which part?Can any one plz help me with this 2nd q of w12 53 http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w12_qp_53.pdf
Yea, you calculated the mass of the solid and that of water correct. But the solubility would be grams of solid/ 100g of water.i labelled my coloums as
mass of water/gm (C-B)
mass of solid/gm (E-D)
and i calculated solubilty by diving (E-D)/(C-B) i.e F/E.
Did i did correct? Thank you.
Yea, you calculated the mass of the solid and that of water correct. But the solubility would be grams of solid/ 100g of water.
mass of solid/ 100gyeah! for example i calculated the mass of solid 2.0 gm, so wouldn't my solubility would be mass of solid( 2gm)/mass of water(which i calculated using C-B) or it would be mass of solid/100
h
here u go
b partwith which part?
mass of solid/ 100g
yea i did... that's what i was told btw...shoot... I'm sorry...now i'm confusedbut you said solubility is mass of solid/mass of water *100
bro please help me to calculate solubility of q no 2 of May/june 2011.It is the mass of the solid which dissolved.
yes..please do...bro please help me to calculate solubility of q no 2 of May/june 2011.
may all of you get A's and A*
which variant ?yes..please do...
yes..please do...
v3 i think...it's l8..i'm actually very sleepy..spent my life's energy on p5 the whole daywhich variant ?
v.53 is about moles ratio ....very easy ...........calculate mass of lead (C-A) ....then mass of oxygen(C-B) ....the other columns ...get the no. of moles by diving each mass by Ar of the element ....plot a graph of moles of lead against moles of oxygen ,...the slope give u a ratio hence the formula of the compoundv3 i think...it's l8..i'm actually very sleepy..spent my life's energy on p5 the whole day
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