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find the deceleration by 14/0.4=-35 and then distance by 2as=v2-u2 where u was 2.4ms the line was a straight line
Are you sure? Equation of motion was not used?The force wasn't constant throughout the motion, hence we had to take out average force acting on the object, and use the formulae work done = force * distance, for which we get 0.18 m
I guess so. Because the force wasn't constant it was changing with the distance.Are you sure? Equation of motion was not used?
You're getting A in p2..hey guys plz mark me on my answers
q1)
proved the units ...and i gues i found the units fr C correctly
q2)
for radio waves i took the speed of light.....dividd the time by 2 ...and by using the formula s=d/t....i found the distance
Q3)
proved ek to 1.3 and my pq disnce was 0.089 and for graph i drew a negative gradient line
q4)
found the torque...........two foces were weight and reaction...dont remember the last 2 parts
q5)
amplitude wsa 40mm and speed was i suppose 7.5.....and for the waves i drew a straight line........in the lsat 2 parts i wrote progrssve and transverse
q6)
proved the resistance..........found the current and power...and for the lst prt i wrote power loss would reduce...
q7)
the driection remaind same....by increang the spacing and dcrsing the voltage we can reduce electic field
q8)
for alpha and beta i wrote about the charges...thier mases....discontinous and continous spectrum and the last part was very easy...
hey guys plz mark me on my answers
q1)
proved the units ...and i gues i found the units fr C correctly
q2)
for radio waves i took the speed of light.....dividd the time by 2 ...and by using the formula s=d/t....i found the distance
Q3)
proved ek to 1.3 and my pq disnce was 0.089 and for graph i drew a negative gradient line
q4)
found the torque...........two foces were weight and reaction...dont remember the last 2 parts
q5)
amplitude wsa 40mm and speed was i suppose 7.5.....and for the waves i drew a straight line........in the lsat 2 parts i wrote progrssve and transverse
q6)
proved the resistance..........found the current and power...and for the lst prt i wrote power loss would reduce...
q7)
the driection remaind same....by increang the spacing and dcrsing the voltage we can reduce electic field
q8)
for alpha and beta i wrote about the charges...thier mases....discontinous and continous spectrum and the last part was very easy...
You're getting A in p2..
yap....i know i messed up tht part..If u wrote
If u wrote transverse and progressive why did u draw a straight line, it wasn't a stationary wave, the new wave drawn should have been 1/4 of the wavelength towards the right.
i cant tell anything about 2 as everyone's confused..pq should have been 0.18...amplitude 20mm(i did this wrong as well)..and wave 1/4 to the right..and power loss would increase as resistance increases with decreasing cross sectional area.other then that all looks good.hey guys plz mark me on my answers
q1)
proved the units ...and i gues i found the units fr C correctly
q2)
for radio waves i took the speed of light.....dividd the time by 2 ...and by using the formula s=d/t....i found the distance
Q3)
proved ek to 1.3 and my pq disnce was 0.089 and for graph i drew a negative gradient line
q4)
found the torque...........two foces were weight and reaction...dont remember the last 2 parts
q5)
amplitude wsa 40mm and speed was i suppose 7.5.....and for the waves i drew a straight line........in the lsat 2 parts i wrote progrssve and transverse
q6)
proved the resistance..........found the current and power...and for the lst prt i wrote power loss would reduce...
q7)
the driection remaind same....by increang the spacing and dcrsing the voltage we can reduce electic field
q8)
for alpha and beta i wrote about the charges...thier mases....discontinous and continous spectrum and the last part was very easy...
Can the force on the wheel be air resistance?
Ans for q2 was 120m and pq is 0.18m and the wave was transverse and progressive.Can anyone please confirm the answers of number 2. And I factor that is it a stationary or a transverse wave. An I think the distance PQ was not 0.089, it was rather 0.18.
how can air resistance act on a wheel? I think the ans was weight of the wheel and the normal reaction force between the pin and the wheel.EXACTLY !!!! THAT IS EXACTY WHAT I WROTE !!!
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