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Physics MCQs thread.

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It's because the direction of electric field will be from the more positive plate to the less positive plate.
 
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yubakkk said:
Hateexams93 said:
Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP =  0.25WQ B WP = 0.5 WQ C WP = 2WQ D WP = 4WQ
hey first find f for both using f=kx x iz same for both
then use wd =1/2fx
i did and i got C , but its wrong :(
 
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A tuning fork of pitch 2.4 kHz is placed near the mouth of a long cylindrical container
which is fully filled with water. Water is slowly drained from the bottom of the container.
Resonance is first heard when the water level had dropped 3.4 cm below the mouth of
the container. At which position of water below the mouth of the container will the next
resonance be heard? Assume the speed of sound in air = 3.4 x 102 m s-1.
A 7.1 cm
B 8.0 cm
C 10.2 cm
D 10.5 cm
 
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qn 21 ans is C as-----d sin Q= n lamda
1.15*10^-6 *sin (60/2)= 1 * lamda (n= 1 for monochromatic light)
so wavelength = 575 nm ....hope this helps
 
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A parallel beam of light of wavelength 450 nm falls normally on a diffraction grating which has
300 lines / mm.
What is the total number of transmitted maxima?
A 7
B 8
C 14
D 15
 
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hassam said:
A tuning fork of pitch 2.4 kHz is placed near the mouth of a long cylindrical container
which is fully filled with water. Water is slowly drained from the bottom of the container.
Resonance is first heard when the water level had dropped 3.4 cm below the mouth of
the container. At which position of water below the mouth of the container will the next
resonance be heard? Assume the speed of sound in air = 3.4 x 102 m s-1.
A 7.1 cm
B 8.0 cm
C 10.2 cm
D 10.5 cm

Is the answer C?
 
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arlery said:
A parallel beam of light of wavelength 450 nm falls normally on a diffraction grating which has
300 lines / mm.
What is the total number of transmitted maxima?
A 7
B 8
C 14
D 15

total maxima = 2*highest maxima +1
highest maxima = line spacing/wavelenght
line spacing = 1/300*10^3
wavelenght = 450nm
 
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Hateexams93 said:
yubakkk said:
Hateexams93 said:
Two springs P and Q both obey Hooke’s law. They have spring constants 2k and k respectively.
The springs are stretched, separately, by a force that is gradually increased from zero up to a
certain maximum value, the same for each spring. The work done in stretching spring P is WP,
and the work done in stretching spring Q is WQ.
How is WP related to WQ?
A WP =  0.25WQ B WP = 0.5 WQ C WP = 2WQ D WP = 4WQ
hey first find f for both using f=kx x iz same for both
then use wd =1/2fx
i did and i got C , but its wrong :(
its ans is c its alright
 
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hassam said:
A tuning fork of pitch 2.4 kHz is placed near the mouth of a long cylindrical container
which is fully filled with water. Water is slowly drained from the bottom of the container.
Resonance is first heard when the water level had dropped 3.4 cm below the mouth of
the container. At which position of water below the mouth of the container will the next
resonance be heard? Assume the speed of sound in air = 3.4 x 102 m s-1.
A 7.1 cm
B 8.0 cm
C 10.2 cm
D 10.5 cm
D
 
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Zishi said:
hassam said:
A tuning fork of pitch 2.4 kHz is placed near the mouth of a long cylindrical container
which is fully filled with water. Water is slowly drained from the bottom of the container.
Resonance is first heard when the water level had dropped 3.4 cm below the mouth of
the container. At which position of water below the mouth of the container will the next
resonance be heard? Assume the speed of sound in air = 3.4 x 102 m s-1.
A 7.1 cm
B 8.0 cm
C 10.2 cm
D 10.5 cm
D

me ka b D cuming
 
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minnienerd said:
can u explain why is it D ??

wavelenght=speed/frequency
second resonance occurs at 3/4 of wavelenght
ull get the answer. change the answer from metres to cm
 
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Hmm, what about May/June 2004 Questions 15 and 27? Help is appreciated.
With Question 15, the net moment should be 40Nm anticlockwise, but it's apparently clockwise in the mark scheme.
 
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How can I solve this?
 

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