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Physics MCQs thread.

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arlery said:
How can I solve this?

% contraction is contraction/original lenght*100 = strain*100
fine the area by pie*(d/2)^2
tention/area=stress
stress/young modulus = strain
strain*100=ans
 
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How do we get 12J as the answer?
 

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@arlery..
Look when trolley of mass 2kg moves with 2ms-1 to the left, that shows that trolley of mass 1kg moves to the right with a velocity of 4ms-1 ...
Now add the individual kinetic energies to get 12 joule ..
 
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Betelgeuse said:
@arlery..
Look when trolley of mass 2kg moves with 2ms-1 to the left, that shows that trolley of mass 1kg moves to the right with a velocity of 4ms-1 ...
Now add the individual kinetic energies to get 12 joule ..

How do we know it moves with 4ms-1 to the right?
 
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arlery said:
Betelgeuse said:
@arlery..
Look when trolley of mass 2kg moves with 2ms-1 to the left, that shows that trolley of mass 1kg moves to the right with a velocity of 4ms-1 ...
Now add the individual kinetic energies to get 12 joule ..

How do we know it moves with 4ms-1 to the right?

its the conservation of momentum:

Initial momentum = 0,
final total momentum = 2(-2) + 1(v) = 0
therefore v = 4 (to the right, since I took 2 ms^-1 to the left)

the find the total K.E., and this the energy which was stored in the spring as strain energy.
 
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arlery said:
How do we get 12J as the answer?


Find the Speed for the 1 kg trolley

M^1*V^1=M^2*V^2

2kg * 2ms^-1 = !kg* X

You get $4 kgms^-1

No find kinetic energy for the trolley And add them
you get 4+8=12
 
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The image should be in png format. Just click on post reply and click upload attachment.
 
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Saturation said:
I have no idea! why isn't it A?

make a second wave to the right of the original wave. u will see that A is moving down while C is moving upwards
 
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