Physics MCQs thread.

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there is one forward force in horizontal direction and one normal force so ans is B
 
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hassam said:

Ok so first of all fringe separation, x, is only changed by things in this formula; x= λD/a

This eliminates three of the options. Light will somehow bend towards bottom when passing through that glass, so fringe pattern will shift to bottom.
 
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why its forward ?i thought the friction force will act in opposite direction , as it says total force exerted by the road
 
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A narrow beam of monochromatic light is incident normally on a diffraction grating. Third-order
diffracted beams are formed at angles of 45
o to the original direction.
What is the highest order of diffracted beam produced by this grating?
A 3rd B 4th C 5th D 6th
HOW TO SOLVE THIS ? :eek:
 
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32 The filament of a 240 V, 100 W electric lamp heats up from room temperature to its operating
temperature. As it heats up, its resistance increases by a factor of 16.
What is the resistance of this lamp at room temperature?
A 36 Ω B 580 Ω C 1.5 kΩ D 9.2 kΩ
does this factor of 16 means 1/16...i am cnfused cos at the same time he says resistance has increased
 
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hassam said:
U MEAN LIGHT WILL GET DIFFRACTED AT THAT EDGE OF GLASS RYT.....?

I don't know if "diffraction" is proper word to use, but what I can safely say is that it bends.
 
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hassam said:
32 The filament of a 240 V, 100 W electric lamp heats up from room temperature to its operating
temperature. As it heats up, its resistance increases by a factor of 16.
What is the resistance of this lamp at room temperature?
A 36 Ω B 580 Ω C 1.5 kΩ D 9.2 kΩ
does this factor of 16 means 1/16...i am cnfused cos at the same time he says resistance has increased

The operating values of power and voltage are the values when it heats up. At that time its resistance = 576 ohms, and at room temperature it's 16 times this value, s0 576/16 = 36 ohm. A must be the answer.
 
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A narrow beam of monochromatic light is incident normally on a diffraction grating. Third-order
diffracted beams are formed at angles of 45
o to the original direction.
What is the highest order of diffracted beam produced by this grating?
A 3rd B 4th C 5th D 6th
HOW TO SOLVE THIS ? ?????????
 
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Hateexams93 said:
A narrow beam of monochromatic light is incident normally on a diffraction grating. Third-order
diffracted beams are formed at angles of 45
o to the original direction.
What is the highest order of diffracted beam produced by this grating?
A 3rd B 4th C 5th D 6th
HOW TO SOLVE THIS ? :eek:

First of all find the ratio d/λ using using "dsin(theta)=nλ putting n=3 and theta = 45

then use value of this ratio by again using the same formula but putting sin(theta) = 1 because this is its max value. This way you'll get value of new n in decimal form. The answer will be the whole number just below that decimal value.

EDIT: I guess you must wait at least for an hour before copying, pasting and posting the question again. =/
 
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Zishi said:
Hateexams93 said:
A narrow beam of monochromatic light is incident normally on a diffraction grating. Third-order
diffracted beams are formed at angles of 45
o to the original direction.
What is the highest order of diffracted beam produced by this grating?
A 3rd B 4th C 5th D 6th
HOW TO SOLVE THIS ? :eek:

First of all find the ratio d/λ using using "dsin(theta)=nλ putting n=3 and theta = 45

then use value of this ratio by again using the same formula but putting sin(theta) = 1 because this is its max value. This way you'll get value of new n in decimal form. The answer will bt the whole number just below that decimal value.

EDIT: I guess you must wait at least for an hour before copying, pasting and posting the question again. =/

The ans is B rite?
 
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aliya_zad said:
Zishi said:
Hateexams93 said:
A narrow beam of monochromatic light is incident normally on a diffraction grating. Third-order
diffracted beams are formed at angles of 45
o to the original direction.
What is the highest order of diffracted beam produced by this grating?
A 3rd B 4th C 5th D 6th
HOW TO SOLVE THIS ? :eek:

First of all find the ratio d/λ using using "dsin(theta)=nλ putting n=3 and theta = 45

then use value of this ratio by again using the same formula but putting sin(theta) = 1 because this is its max value. This way you'll get value of new n in decimal form. The answer will bt the whole number just below that decimal value.

EDIT: I guess you must wait at least for an hour before copying, pasting and posting the question again. =/

The ans is B rite?

Yep.
 
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