Physics MCQs thread.

[libra94]

no no, thats emf of the battery, terminal voltage is around the component

 

[kirashinagami]

hey, please answer my phy mcq questions here... thanks a lot

viewtopic.php?f=26&t=9458

 

[MHHaider707]

no one knows this ?? none of u are giving ans yar//////
any one try??

Hey yubakkk......is the answer C??

 

[yubakkk]

ans iz b can u xplain??

 

[Xthegreat]

any one has xplain this answer?? in which page??

Q5 O/N10
rotating 3000 revolutions per minute
meaning 1 revolution = 60/3000 = 0.02s

now moving to the answers.
A. 1s
B. 0.01s
C. 0.0001s
D. 0.0000001s

so obviously its B

 

[yubakkk]

is it da way 2 solve??dear xtegreat

 

[yubakkk]

this isnt answered any one????

 

[yubakkk]

hey zishi can u xplain this?????or any one??

 

[Xthegreat]

yup. the question wants to know at which time base setting we can see and differentiate impulses clearly

if we use A, then the impulses will b too close togther
C and D are too large that one impulse cannot fit into the 10cm screen.

 

[Xthegreat]

this isnt answered any one????

whats the ans? c?

 

[MHHaider707]

this isnt answered any one????

Is it A???

 

[sakibfaiyaz]

It should be D,
Gravitational pull depends on the gravitational field of the earth; which remains same throughout.
Pressure exerted on the VERTICAL SIDES (left and right) is SAME (pascals law).
Pressure difference between horizontal sides (top and bottom) would result in upthrust!
but Since that is not an option, D is the only right answer

 

[sakibfaiyaz]

And obviously A and B wont be the answer. A wont be because pressure DIFFERENCE will always remain constant, therefore upthrust constant.
And B wont be the answer as reading corresponds to= weight - upthrust, not just upthrust

 

[rabib2013]

can anyone help me out with this?

 

[Zishi]

can anyone help me out with this?

As in two sides of the tube, the same liquid has the same height, x, so on those two points pressure will be equal. We've to look above those points. On right, the same liquid is at height x units from the "same" pressure point(which is x units from turning of tube). On left, the liquid above the point having "same" pressure is 2x units above it. As it is in equilibrium, so

Pressure of second liquid on left at height 2x from "same" pressure point.= pressure of first liquid at height x from "same" pressure point.

Solve this equation, and you'll get the answer.

 

[hassam]

 

[kirashinagami]

hey friends here, please help me with 5 physic mcq questions on this link viewtopic.php?f=26&t=9458

please anyone - zishi hassam xthegreat mhraider yubakk etccc,
i would be very grateful to you

 

[Zishi]

B

 

[rabib2013]

hey zishi, there are these questions from may june 01, number 2, 11 and 33.. i can't find its mark scheme anywhere. :\
can u tell me their answers? esp no 2

 

[Zishi]

hey zishi, there are these questions from may june 01, number 2, 11 and 33.. i can't find its mark scheme anywhere. :\
can u tell me their answers? esp no 2

I don't have that paper.