Physics MCQs thread.

[arlery]

Q 36 M/J 2010 V11
urgent plzzz explain your ans plzzzz

It's C because this arrangement will give the highest current.

 

[diwash]

@deathdealer..u have been ignoring my answer...i will not answer ur Q any more

 

[cocospaniel]

Can someone help solve the hardest question in the world november 2010 q9, variant 1? :%)

 

[jumana94]

@ basoom
dude thats easy, it seems u still dont get how to do it....
when u have resistors in series, u jus add their resistance (R1+R2+R3...)
if they were in parallel, u find the reciprocal of (1/R1+1/R2+1/R3....)
so the answer is D in this case

 

[diwash]

@ cocospaniel...write the Q no...

 

[cocospaniel]

@ cocospaniel...write the Q no...

Question 9!

 

[basoom16]

@ basoom
dude thats easy, it seems u still dont get how to do it....
when u have resistors in series, u jus add their resistance (R1+R2+R3...)
if they were in parallel, u find the reciprocal of (1/R1+1/R2+1/R3....)
so the answer is D in this case

i hate electricity

 

[basoom16]

how do u get the current i know how to get the resistance

 

[mrpaudel]

Q 36 M/J 2010 V11
urgent plzzz explain your ans plzzzz

Jus check out..which one has lowest total resistance has got highhest ammeter reading!!

 

[diwash]

@cocospaniel....look in this Q u have been told that the Collision in inelastic...if it would have been elastic the Answer would have been D..other answers can be easily eliminated as they donot concern with either elastic or inelastic colision...

 

[cocospaniel]

http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w10_qp_11.pdf

explain qs 9 plz

use the formula v^2 = u^2 + 2as
where
positive direction = direction of train
u = original velocity (speed of train)
v = final velocity (zero)
a = acceleration of train (in this case, acceleration is negative)
s = distance (from point where velocity = u to where velocity = v)

The problem uses x for distance, not s, so the equation we'll use is v^2 = u^2 + 2ax

because v = 0, we can write
u^2 + 2ax = 0, rearranging as:
x = -(u^2) / 2a . . . . . . . . Note - a has a negative value, thus making x positive
x = Ku^2 where K = -1 / (2a)
ie. x varies as the square of u
so if u increases by 20% (ie changes by a factor of 1.2), then x will change by a factor of (1.2)^2
which is a factor of 1.44
thus the minimum distance between yellow and red must now be 1.44x

 

[DeathDealer]

@deathdealer...
the answer is A..unlike other options...in A when small mass(less heavy) is added the spring with less k will extend properly( the box will not disturb its expansion) so its sensitive to less heavy mass..but then heavy mass is added...the spring with small k will extend much..and its extension is disturbed by the cage..so is less sensative...
hope u got it

Ummmmmm......yeah got it buh lila bih yaaaaWr :/
Less k meanx more Extention
Less weight small extention n Heavy Weight LARGE extention !
And da Cage Supportx da LOW k so dat it don Break
BUT
Fo dah HIGH k Less mass wud hav less Extention Where az Heavy Mass REsultx MORE EXTENTION
HOW MORE HEAVY IZ LESS SENSATIVE ?

 

[shyqueen]

does anyone ov yu hav da marking scheme of june 2001?? can yaa plzz post it!!

 

[ciraphla]

how does 20% gives us increase in factor by 1.2?

 

[basoom16]

question 1
october nover 09

 

[ciraphla]

@cocospanial oh okay i got that thanks alot!

 

[cocospaniel]

how does 20% gives us increase in factor by 1.2?

u^2 is proportional to x
u^2 has a factor of 1. An increase of 20% is 1.2. (20% of 1) + 1 = 1.2

 

[cocospaniel]

@cocospanial oh okay i got that thanks alot!

Your welcome

 

[jumana94]

mark scheme of june 2001
1.B
2.D
3.C
4.C
5.B
6.B
7.B
8.B
9.C
10.C
11.D
12.D
13.A
14.D
15.D
16.D
17.C
18.B
19.C
20.C
21.B
22.C
23.C
24.A
25.A
26.
27.
28.
29.
30.B
31.B
32.B
33.B
34.C
35.
36.
37.C
38.B
39.D
40.B

here u go, sorry there are some questions that i dnt have :/ good luck

 

[MHHaider707]

Anyone please help me in Q.31 n 34 of O/N 10 12

http://www.xtremepapers.me/CIE/Internat ... _qp_12.pdf