• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics MCQs thread.

J

jumana94

Messages
45
Reaction score
4
Points
18
@ basoom
dude thats easy, it seems u still dont get how to do it....
when u have resistors in series, u jus add their resistance (R1+R2+R3...)
if they were in parallel, u find the reciprocal of (1/R1+1/R2+1/R3....)
so the answer is D in this case :)
 
B

basoom16

Messages
10
Reaction score
0
Points
0
jumana94 said:
@ basoom
dude thats easy, it seems u still dont get how to do it....
when u have resistors in series, u jus add their resistance (R1+R2+R3...)
if they were in parallel, u find the reciprocal of (1/R1+1/R2+1/R3....)
so the answer is D in this case :)
Click to expand...


i hate electricity :p
 
D

diwash

Messages
234
Reaction score
7
Points
28
@cocospaniel....look in this Q u have been told that the Collision in inelastic...if it would have been elastic the Answer would have been D..other answers can be easily eliminated as they donot concern with either elastic or inelastic colision...
 
C

cocospaniel

Messages
72
Reaction score
1
Points
0
ciraphla said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w10_qp_11.pdf

explain qs 9 plz
Click to expand...

use the formula v^2 = u^2 + 2as
where
positive direction = direction of train
u = original velocity (speed of train)
v = final velocity (zero)
a = acceleration of train (in this case, acceleration is negative)
s = distance (from point where velocity = u to where velocity = v)

The problem uses x for distance, not s, so the equation we'll use is v^2 = u^2 + 2ax

because v = 0, we can write
u^2 + 2ax = 0, rearranging as:
x = -(u^2) / 2a . . . . . . . . Note - a has a negative value, thus making x positive
x = Ku^2 where K = -1 / (2a)
ie. x varies as the square of u
so if u increases by 20% (ie changes by a factor of 1.2), then x will change by a factor of (1.2)^2
which is a factor of 1.44
thus the minimum distance between yellow and red must now be 1.44x :D
 
D

DeathDealer

Messages
55
Reaction score
0
Points
16
diwash said:
@deathdealer...
the answer is A..unlike other options...in A when small mass(less heavy) is added the spring with less k will extend properly( the box will not disturb its expansion) so its sensitive to less heavy mass..but then heavy mass is added...the spring with small k will extend much..and its extension is disturbed by the cage..so is less sensative...
hope u got it
Click to expand...

Ummmmmm......yeah got it buh lila bih yaaaaWr :/
Less k meanx more Extention
Less weight small extention n Heavy Weight LARGE extention !
And da Cage Supportx da LOW k so dat it don Break
BUT
Fo dah HIGH k Less mass wud hav less Extention Where az Heavy Mass REsultx MORE EXTENTION
HOW MORE HEAVY IZ LESS SENSATIVE ?
 
J

jumana94

Messages
45
Reaction score
4
Points
18
mark scheme of june 2001
1.B
2.D
3.C
4.C
5.B
6.B
7.B
8.B
9.C
10.C
11.D
12.D
13.A
14.D
15.D
16.D
17.C
18.B
19.C
20.C
21.B
22.C
23.C
24.A
25.A
26.
27.
28.
29.
30.B
31.B
32.B
33.B
34.C
35.
36.
37.C
38.B
39.D
40.B

here u go, sorry there are some questions that i dnt have :/ good luck :)
 
You must log in or register to reply here.
Top