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Physics P-22 GT.

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Can anyone tell me how many marks they will take off if I counted the number of wavelength wrongly (+.5) and carried on using it for the next questions?
The question has 2 marks for the +.5 thing and the next one has 3 marks.
 
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Can anyone tell me how many marks they will take off if I counted the number of wavelength wrongly (+.5) and carried on using it for the next questions?
The question has 2 marks for the +.5 thing and the next one has 3 marks.
V21 or 22? And I'm sure there will be ecf so most probably if ur method for the second part is correct u will get all 3 marks but loose 2 for incorrectly counting the wavelength
 
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As the thread title mentioned, P22. I thought I could at least get 1 mark for getting the number of wavelength and do the calculation correctly. Anyway, thank you!
 
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When do they ever ask us to calculate the NUMBER of wavelengths? That statement in itself doesn't make sebse :S
 
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I prepared for the Difficult and it was dayum too easy, so I was Trolled BY Cambridge and s messed things up quite badly! But IA I ll still be lying in the appropriate range :(
 
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Guys we had to calculate the slit separation so we have to count the no. of wavelengths because in lamda = ax/D, the x is fringe separation...I did it but cancelled it coz it was written not to scale on the diagram....
 
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Guys we had to calculate the slit separation so we have to count the no. of wavelengths because in lamda = ax/D, the x is fringe separation...I did it but cancelled it coz it was written not to scale on the diagram....
 
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Guys we had to calculate the slit separation so we have to count the no. of wavelengths because in lamda = ax/D, the x is fringe separation...I did it but cancelled it coz it was written not to scale on the diagram....
Why did u cancel it!! What u did was correct
 
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Can anyone tell me how many marks they will take off if I counted the number of wavelength wrongly (+.5) and carried on using it for the next questions?
The question has 2 marks for the +.5 thing and the next one has 3 marks.
ecf will save you brother :p
 
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Did the potential difference increase as the resistance increased in that resistance current graph q

Guys we had to calculate the slit separation so we have to count the no. of wavelengths because in lamda = ax/D, the x is fringe separation...I did it but cancelled it coz it was written not to scale on the diagram....
you just had to divide the fringes total distance by number of fringes.. youll get x... then use the formula lambda=ax/d I guess thats how it was supposed to be done
 
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