- Messages
- 175
- Reaction score
- 13
- Points
- 28
ehm ehm
i wanted to make a point
that it was v-t graph
not of the g
was not the graph gradient
this is because the air resistance will be built at first stage
as soon as v is more than zero
so the acceleration of rain drop is revised by the gradient of the graph this is because as resistance increasr if the speeed increases
so the fact is that it can never the g value practically
so the accleration of the second rain particle is more
than it should be for the first rain drop altough tht too imnt the second drop will not reach g cuz air resistance cant be imagined in this situation.
Due to this fact the gradient will be more.
know we will reach to the second fact
which the terminal velocity of the rain will be higher
and it is too obviously why
F=ma
Density=m/v
so if density is 1000 means if volume decreases if radius decreases so the mass should decrase
i accept
but
F=ma
and as the acceleration of the second drop is more than the first this mass can be very of smaallll effct
on equation
so still the force of gravity is constant and air resistance less,so more acceleration so little more than the first one
Im ready to accept any reason against this.......With proper explanation
Im here standing to the base
Wsalam
i wanted to make a point
that it was v-t graph
not of the g
was not the graph gradient
this is because the air resistance will be built at first stage
as soon as v is more than zero
so the acceleration of rain drop is revised by the gradient of the graph this is because as resistance increasr if the speeed increases
so the fact is that it can never the g value practically
so the accleration of the second rain particle is more
than it should be for the first rain drop altough tht too imnt the second drop will not reach g cuz air resistance cant be imagined in this situation.
Due to this fact the gradient will be more.
know we will reach to the second fact
which the terminal velocity of the rain will be higher
and it is too obviously why
F=ma
Density=m/v
so if density is 1000 means if volume decreases if radius decreases so the mass should decrase
i accept
but
F=ma
and as the acceleration of the second drop is more than the first this mass can be very of smaallll effct
on equation
so still the force of gravity is constant and air resistance less,so more acceleration so little more than the first one
Im ready to accept any reason against this.......With proper explanation
Im here standing to the base
Wsalam