• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
4,609
Reaction score
3,903
Points
323
i)Amplitude is 7.6mm which you can see it from the graph (the highest displacement)
ii) 180 (This is 180 because, one graph is completed in 80cm.....So in 80cm 360 degree is completed. So there is a phase difference of 40cm between the point. So it is half of 80com and hence it is half of 360, which is 180.......Or you could use this formula- (40/80)*360 which is the normal formula of phase difference)
iii) V=frequency * wavelength
= 15 * 0.8
=12
(b) This one i have to show you by drawing....if you are interested then i can show you
(c)
i. Zero (Since they are on the same wave and phase)
(ii)
Antinode- A region in which two amplitude are at its highest point in opposite direction
Node- A region where two waves intersect and have no displacement

(iv) Again, i have to draw this...if you are interested then i could give a separate PDF for this by drawing in computer


Yep. i also want the graphs :p ;) :)

thanks alot
 
Messages
318
Reaction score
328
Points
73
please someone answer the question i have posted above on this page its the second time i posted them:( !!
 
Messages
258
Reaction score
99
Points
28
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_qp_21.pdf
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w10_ms_21.pdf
Q 2(b) and Q 6(a ii) Can someone show exactly how these both are drawn? i have read the mark scheme and examiner report but i might be thinking it is drawn some other way entirely so just to verify my own drawings.

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w09_qp_21.pdf
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w09_ms_21.pdf
Q 7(b) in this i also want to confirm if my drawing is correct so if someone else can show the correct one..

here you go love :D


nuclei.png

lamp.png

GA.png
 
Messages
43
Reaction score
19
Points
18
Any force increases if you apply that force from a distance. More the distance, more the force increases. Thats why we use a can opener to open the coke bottle. As it has a handle, it provide a distance and hence the force increases. similarly, the question asked that, what could make the weight increase its force...... The weight can increase its force if the if it is moved rightward as it gives a greater distance from the pivot
 
Messages
258
Reaction score
99
Points
28

for question 3cii move the pivot closer to the end of the ruler so that weight of ruler has more momentum since momentum =f x s greater s means greater momentum

6b)
molecules collide with the walls
molecules exert equal and opposite force on wall
pressure is averaging effect of many collisions


 
Messages
43
Reaction score
19
Points
18
yes please attach the graphs for both parts.
The red wave represent the phase after 0.25T....Since it is 0.25, it means that the two graph has a phase difference of 1/4 since 1/4= 0.25
It means that the next graph would be one fourth ahead.... And what is the one fourth of 80? It would be 20....so the new graph would complete one complete wave 20 steps after the old graph and that would be 100 as 80+20=100

If it helped anyone then can some one help me with my probs.....
m/j 2007- 5b (ii)
m/j 2011 21- 2c(i) 5 (ii)b
m/j 2011 22 5b(ii) 6(ii)1
 

Attachments

  • Capture3.PNG
    Capture3.PNG
    10.6 KB · Views: 10
Messages
43
Reaction score
19
Points
18
Yep. i also want the graphs :p ;) :)

thanks alot
The red wave represent the phase after 0.25T....Since it is 0.25, it means that the two graph has a phase difference of 1/4 since 1/4= 0.25
It means that the next graph would be one fourth ahead.... And what is the one fourth of 80? It would be 20....so the new graph would complete one complete wave 20 steps after the old graph and that would be 100 as 80+20=100

If it helped anyone then can some one help me with my probs.....
m/j 2007- 5b (ii)
m/j 2011 21- 2c(i) 5 (ii)b
m/j 2011 22 5b(ii) 6(ii)1
 

Attachments

  • Capture3.PNG
    Capture3.PNG
    10.6 KB · Views: 4
Top