Physics: Post your doubts here!

[KurayamiKimmi]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s06_qp_2.pdf
someone pretty please help me out with question no 2-c-ii ^_^

 

[Secret Crowds]

how do i calculate the uncertaintiy in june 2011 varient 1 ''9072/21'' question 1

 

[Unicorn]

thanx

welcome ^^

 

[Unicorn]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_2.pdf
someone pretty please help me out with question no 2-c-ii^_^

well you know that the system in is in equilibrium because it is not moving, so all upwards forces must equal all downwards forces

so fsinα + tsin
β = W

 

[freakybandi]

please someoone help!!!! summer 09 variant 1 qs 5b!!!...thats da second time m posting this!!
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s09_qp_2.pdf

 

[Most_UniQue]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_2.pdf

Q6b plz help!! Plzz!!

 

[hmlahori]

here you go love


View attachment 11333

View attachment 11330

View attachment 11329

The first graph you attached is obviously wrong cuz its an alpha particle and there will be deflection when it passes by the nucleus.
In the second graph the shape of my graph is similar but what will be the labelling of the y-axis?
And the third attachment is very much like how i drew it and is desribed in the mark scheme so at least i've got that one correct!

 

[iKhaled]

need help with paper nov oct 2010

Q6 a) ii..how can i draw the line, why is it a straight line from the origin then curved at the end? can someone please explain that?

http://www.xtremepapers.com/papers/...nd AS Level/Biology (9700)/9700_w10_qp_21.pdf

 

[Unicorn]

The first graph you attached is obviously wrong cuz its an alpha particle and there will be deflection when it passes by the nucleus.
In the second graph the shape of my graph is similar but what will be the labelling of the y-axis?
And the third attachment is very much like how i drew it and is desribed in the mark scheme so at least i've got that one correct!

yeah but if you look at the alpha particle before it only has a slight deflection so the one above is most likely to go undeflected if not a puny deflection

 

[Most_UniQue]

yeah but if you look at the alpha particle before it only has a slight deflection so the one above is most likely to go undeflected

It must have slight defelection .

Can you help me with 6b of this paper

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_2.pdf

 

[Unicorn]

need help with paper nov oct 2010

Q6 a) ii..how can i draw the line, why is it a straight line from the origin then curved at the end? can someone please explain that?

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Biology (9700)/9700_w10_qp_21.pdf

honey that is bio

 

[hmlahori]

yeah but if you look at the alpha particle before it only has a slight deflection so the one above is most likely to go undeflected if not a puny deflection

no it will experience deflection because it does pass near to the nucleus but wat i just did realise is that the deviation will be after the one for the other particle and will have a smaller deviation angle than the other particle because of being further away form the nucleus.

 

[iKhaled]

honey that is bio

http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w10_qp_21.pdf

here is the correct paper..so sorry, my mind is overloaded and i cant even think :S

 

[Unicorn]

It must have slight defelection .

Can you help me with 6b of this paper

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_2.pdf

ok then
for the first row the power dissipated is obviously 0 because the circuit is incomplete so no electricty will flow
2nd row current will always go through the route with less resistance so power is 1.5kW as current "avoids" B
3rd current will only flow through A + C so total is 3.0kW
4th p= V^2/r since the resistors are in series voltage is shared equally since they have same electrical requirements so V is halfed while R remains constant so new voltage is (0.5v)^2 which is 0.25v^2 so P= 2*(0.25*240^2)/38.4 =750
5th 0.75kW + 1.5kW =2.25kW

hope it helped : D

 

[Unicorn]

http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w10_qp_21.pdf

here is the correct paper..so sorry, my mind is overloaded and i cant even think :S

It is straight at beginning because of Ohm's law which says that V is proportional to I as long as TEMP is CONSTANT so in the begining temp is constant
but after a while the bulb heats up so the graph curves because it no longer abides by ohm's law

 

[iKhaled]

View attachment 11374

It is straight at beginning because of Ohm's law which says that V is proportional to I as long as TEMP is CONSTANT so in the begining temp is constant
but after a while the bulb heats up so the graph curves because it no longer abides by ohm's law

thank u

 

[Unicorn]

thank u

welcome :-D

 

[Unicorn]

Can someone please help me in question 4c

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_qp_22.pdf
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s10_ms_22.pdf

I understand that the lowest sound would be at an antinode but then why is the wavelength 1.8m not 2.4m

 

[Most_UniQue]

ok then
for the first row the power dissipated is obviously 0 because the circuit is incomplete so no electricty will flow
2nd row current will always go through the route with less resistance so power is 1.5kW as current "avoids" B
3rd current will only flow through A + C so total is 3.0kW
4th p= V^2/r since the resistors are in series voltage is shared equally since they have same electrical requirements so V is halfed while R remains constant so new voltage is (0.5v)^2 which is 0.25v^2 so P= 2*(0.25*240^2)/38.4 =750
5th 0.75kW + 1.5kW =2.25kW

hope it helped : D

Y does the current avoid B in 2nd? And what do you mean 2nd row current will always go through less resistance route?

 

[Unicorn]

Y does the current avoid B in 2nd? And what do you mean 2nd row current will always go through less resistance route?

well i have been taught to think of current as a living thing and that wires are passageways where current walks freely in. resistors are a like narrow tunnels funneling the current to go in as "a single line" so if there is a less narrow route the current will go through it which is in this case S2 as it has no resistance