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Which part do you specifically need aid with?
part (a) (i) change in gravitational potential energy.
The gravitational potential energy has the formula GMm/x where x is the distance. We have to calculate the change in GPE so we will find the difference for each of the quantities in the formula. G M and m are constant, and hence the only thing that varies is the x. Now x is equal to the difference in the two distances. One being the (R + h1) and other being the (R + h2). h1 and h2 are distances from the surface of earth, whereby we need the distances from the centre of the earth.
thank u so much..The gravitational potential energy has the formula GMm/x where x is the distance. We have to calculate the change in GPE so we will find the difference for each of the quantities in the formula. G M and m are constant, and hence the only thing that varies is the x. Now x is equal to the difference in the two distances. One being the (R + h1) and other being the (R + h2). h1 and h2 are distances from the surface of earth, whereby we need the distances from the centre of the earth.
Hence the final formula would become {GMm/(R+h1)} - {GMm/(R+h2)}. You could simplify this to get to the answer in the marking scheme.
Plz help me with this ques also: Q.5 part (b) of this paper: http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s08_qp_4.pdfThe gravitational potential energy has the formula GMm/x where x is the distance. We have to calculate the change in GPE so we will find the difference for each of the quantities in the formula. G M and m are constant, and hence the only thing that varies is the x. Now x is equal to the difference in the two distances. One being the (R + h1) and other being the (R + h2). h1 and h2 are distances from the surface of earth, whereby we need the distances from the centre of the earth.
Hence the final formula would become {GMm/(R+h1)} - {GMm/(R+h2)}. You could simplify this to get to the answer in the marking scheme.
Well! For this, you just remember that connecting capacitors in series decreases their effective capacitance while being in parallel increases it.(It is almost the same as you used to do with resistors in AS). Anyway, so two resistors in series connected with a similar arrangement in parallel will provide you with an effective capacitance of 4500 uF. (Try calculating the capacitance of the whole arrangement and you'll get the answer 4500 uF which signifies it is correct!
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yaar guyz plz answer my question also.....
Thank u once again..Well! For this, you just remember that connecting capacitors in series decreases their effective capacitance while being in parallel increases it.(It is almost the same as you used to do with resistors in AS). Anyway, so two resistors in series connected with a similar arrangement in parallel will provide you with an effective capacitance of 4500 uF. (Try calculating the capacitance of the whole arrangement and you'll get the answer 4500 uF which signifies it is correct!
yaar guyz plz answer my question also.....
tell me how to prepare for paper 5 in just one day..?
Thank u..Some tips for P5 : http://www.xtremepapers.com/community/threads/physics-p5-some-tips-for-question-1.21570/
All the best
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