We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
cn any 1 explain me oct nov 03 p1-7,8,16,28,31,34
AgreedU THINK IF SOMEONE WOULD SOLVE ALL 40QUESTIONS FOR U THEN STOP DREAMING JUST POST THE QUESTIONS THAT U THINK U CANT SOLVE
thnks.i dint get no. 16.its confusing.u made my confusions clear.thanks a lot7) Speed is the gradient of a displacement time graph. When the gradient is 0 there is no displacement and hence the car is at rest. For the speed while it's moving calculate the gradient between 50 and 100 sec. That is, (70-30)/ (100-50) =.8m/s. So the answer is B.
8) Initially, when the object is dropped it accelerates at 'g' because there is no air resistance. As the object drops further it's velocity increases, so the air resistance acting on it increases and as a result it's acceleration decreases from 'g' to 0 gradually. This statement coincides with graph A, so that's the answer.
16) The vertical component of tension has to be equal to the sum of the vertical component of W and H as the object is in equilibrium. Hence, T has to be the greatest force. The only answer which lists T as the greatest is C.
28) Use the formula dSinθ =nλ , where d is the separation of the rods, θ is the angle of diffraction, n is the order and λ the wavelength.
Find the angle for the second order.
.08Sinθ = 2* .03,
θ= 48.5 degree
Then find the difference in angle between the first and second order. 48.5-22= 26.6
so the answer is B.
31) Calculate the total resistance in the parallel combination.
1/R = 1/6 + 1/3
Therefore R = 2
So the voltage will be divided equally between the resistor of 2.0 Ω in series and the resistors parallel combination. This means the voltage across the parallel combination is 6V.
Now just use V=IR to calculate the current across the 6.0 Ω resistor.
6= I*6
So, I= 1A
The answer is A.
34)Use the ratio of resistance* potential of supply to calculate the potential across the 3.0Ω in X and Y.
For X potential difference across 3.0Ω resistor is (3/3+.5)* 1.5 =1.28 V
For Y potential difference across 3.0Ω resistor is (3/3+2) *1.5 = .9 V
So greater potential across 3.0Ω in X.
P= v^2/R, R is constant (3.0Ω), as the potential is greater in X the power dissipated will also be greater in X.
The answer is B.
for first questioncan you please solve these question thanks a lot
thnks.i dint get no. 16.its confusing.u made my confusions clear.thanks a lot
OH BUddy ur great.nw i got it.ur really geniusOk, Let me try again. For an object to be in equilibrium all the forces as to be balanced, right?
The Tension and H are acting at angles on the plank so they have to be resolved into their vertical and horizontal components when you're calculating the resultant force.
You can form the equation-
vertical component of T = vertical component of H + W
As component of T equals that of H and W, it has to be greater then both forces. Hence T is the largest force. Only answer C lists T as the largest.
Hope this helps!
which question of summer 2004?hey can u solve my mj o4 prblm.pls if u have time
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now