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Physics: Post your doubts here!

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PHY A2 HELP!
http://www.novapapers.com/images/PDF/CIE/A-LEVEL/Physics/2012nov/9702_w12_qp_41.pdf
Q9 bi } I get that we make a square wave but how do we figure out the cross over points?


the graph will be a square wave with the initial coordinate being (0,5)
all the 3 graphs, (that is V1, V2 and Vout graphs) intersect at the same points (all of them above the x-axis)
whenever V2 > V1 , Vout will be +5v
whenever V1 > V2, Vout will be -5V
and at the points where the graphs intersect, there is a straight vertical line from +5 to -5 or vice versa
hope you understand......
Hassi123
 
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please someone post the physics As paper 2 of may june 2002 with mark scheme.i will very thankful for that. May Allah give all of us success
 
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please someone post the physics As paper 2 of may june 2002 with mark scheme.i will very thankful for that. May Allah give all of us success

There you go.....
 

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Aoa wr wb,

Look, when you have a sinusoidal alternating current, it implies that the direction of currents in both of the wires keeps changing directions, and since the currents are in phase, it implies that they have currents flowing in the same direction at any particular time.

Now, the method to obtain the direction of force on wire B, is to use Fleming's Left Hand Rule. But before doing this, the direction of magnetic field experienced by wire B must be obtained by using Right Hand Grip Rule on wire A.
Since the currents are constantly changing, the direction of magnetic field will keep on changing.
However, the force on wire B will always be towards the left (towards wire A) because the direction of magnetic field AND the direction of current are both changing, hence your thumb will subsequently point towards wire A.
The force varies from '0' to a maximum value and the variation is sinusoidal, this is obvious since a sinusoidal alternating current is being applied.
The last statement in the marking scheme which states 'at twice frequency of the current' is what i still quite don't get.

Hope it helped :)
 
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can u please tell me what topics from physics come in the ATP paper? (O-level) like in chemistry its mainly just Acids, Bases n Salts , Rate of reaction and Moles..
PLEASE HELP!
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_2.pdf
No. 2 (b i).. it is a relatively simple question, but I'm kinda confused.
Change in momentum = momentum before - momentum after collision right?
So why did the marking scheme add the two velocities?

Please help me clear the doubt.. thanks!


No. Change in momentum = final momentum - initial momentum = m(v-u)
taking <-- to be +

1.2(0.8) - 1.2(-4)
gives 5.76 Ns in the <-- direction as answer.

or if you take --> to be +

then

1.2(-0.8) - 1.2(4)
gives -5.76 Ns

the change is 5.76 Ns in <-- direction eitherway.
 
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Aoa wr wb,

Look, when you have a sinusoidal alternating current, it implies that the direction of currents in both of the wires keeps changing directions, and since the currents are in phase, it implies that they have currents flowing in the same direction at any particular time.

Now, the method to obtain the direction of force on wire B, is to use Fleming's Left Hand Rule. But before doing this, the direction of magnetic field experienced by wire B must be obtained by using Right Hand Grip Rule on wire A.
Since the currents are constantly changing, the direction of magnetic field will keep on changing.
However, the force on wire B will always be towards the left (towards wire A) because the direction of magnetic field AND the direction of current are both changing, hence your thumb will subsequently point towards wire A.
The force varies from '0' to a maximum value and the variation is sinusoidal, this is obvious since a sinusoidal alternating current is being applied.
The last statement in the marking scheme which states 'at twice frequency of the current' is what i still quite don't get.

Hope it helped :)
Thank you so much. It helped a lot. :)
JazakAllah Khairan.
 
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No. Change in momentum = final momentum - initial momentum = m(v-u)
taking <-- to be +

1.2(0.8) - 1.2(-4)
gives 5.76 Ns in the <-- direction as answer.

or if you take --> to be +

then

1.2(-0.8) - 1.2(4)
gives -5.76 Ns

the change is 5.76 Ns in <-- direction eitherway.
I had got -5.76 Ns but thought that I'm wrong since the marking scheme gave 5.76 as the answer.
Thanks a lot :)
 
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