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No Problem mate!Damn that was simple.
Thank you
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No Problem mate!Damn that was simple.
Thank you
I have a doubt in thisForget the photoelectric effect for a moment. Think about what is meant by the intensity of the radiation of the target surface.
Intensity = power / [target area]
Rearranges to:
power = intensity * area
If you are keeping the intensity constant, and the area of the photo-target is constant, then the power of the incident radiation must also be constant.
Each photon brings with it a certain amount of energy. If you reduce the wavelength, you increase the amount of energy carried by each photon.
The energy delivered = (energy of a photon) * (number of photons)
power = energy / time
So:
power = (energy of a photon) * (number of photons) / time
If the power is constant, and the energy of a photon is increased, then (number of photons / time) must decrease.
Now we are back to the photoelectric effect.
Fewer photons/s = fewer electrons/s = smaller current.
EDIT:
Nope!
The charge on an electron is fixed.
The total charge delivered to the photo-anode = (charge on electron ) * (number of electrons)
Electric current = [charge] / [time]
Current = (charge on electron ) * (number of electrons)/(time)
If you have fewer electrons/second emitted by the photo-surface, you have a smaller current.
How quickly the electrons travel does not change that. (this is what my friend said i got no idea about this)
More intense radiation simply means that more packets of energy (photons) are delivered each second. But the energy of each packet is unchanged. So if there wasn't enough energy to cause photoelectric emission, making it brighter won't change anything,I have a doubt in this
isnt your explanation valid if electron behave like wave but here we are talking abut photo electric effect
nope it isn't in the book and its the first time i've heard of it as far as i knowmy teacher taught me tht...
it isnt thr in d book??
well i just sort it out e is elementary charge we know V=w/q so W=QV=eV simple as that thats how i just find it out dont panic just think and u will go way too aheadnope it isn't in the book and its the first time i've heard of it as far as i know
snowbrood hav u heard of this before??
well i am in AS level this is the answer that my friend gave me i dont know what it means lolMore intense radiation simply means that more packets of energy (photons) are delivered each second. But the energy of each packet is unchanged. So if there wasn't enough energy to cause photoelectric emission, making it brighter won't change anything,
wooaah fancy working out to be done in a paper where u have got just one hour -_-well i just sort it out e is elementary charge we know V=w/q so W=QV=eV simple as that thats how i just find it out dont panic just think and u will go way too ahead
The question specifically asked for the power transformed by battery B that is why we will use 12V in calculation.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_22.pdf
in question 5b
why do we take the voltage to be 12V (as per the ms) .... shouldn't we take it as (12-3) = 9V??
I was calculated correctly in the previous part to be 2.5A
and then
P=IV
=(2.5)(9)
=22.5W ??
the answer given in the ms is 30W
what am i not getting at here?
yeah sorry... i just realized my mistake after i posted the question thanks anywaysThe question specifically asked for the power transformed by battery B that is why we will use 12V in calculation.
since he measured the distance from the top f ball but when the ball hit the table only the bottom of the ball hits the table therefore the y intercept of graph is the diameter of the ball that is approximately 1.75cm according to my line.Hi can anyone please help me with O/N 2010 P23 Q 4 c i, ii Thanks
ur welcomeyeah sorry... i just realized my mistake after i posted the question thanks anyways
ok but wat about the last part of the question... how do we know that the circuit can be used to store energy in A?The question specifically asked for the power transformed by battery B that is why we will use 12V in calculation.
10 b)Aoa wr wb
Can someone please explain
5 b ii - ?
10 b - please provide a detailed explanation for the diagram
11 - i don't understand the last phrase in the ms where it says the crystal is cut.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_42.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_ms_42.pdf
Thank you
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