Physics: Post your doubts here!

[Tabi Sheikh]

why 1250 and 312.5 are out of visible i dont get it

check the spectrum of visible light its from 380 to 750 nm approx.

 

[Tabi Sheikh]

why 1250 and 312.5 are out of visible i dont get it

the wavelength of visible light is between 380 to 750nm

 

[daredevil]

q4 b i) The area between both the graphs..... is the energy Es

but shouldn't the energy expended be below the lower graph?? because the one between the two graphs is recovered?

 

[snowbrood]

check the spectrum of visible light its from 380 to 750 nm approx.

lol chutia me thanks buddy u saved the day

 

[Tabi Sheikh]

lol chutia me thanks buddy u saved the day

no prob dude

 

[Tabi Sheikh]

t

but shouldn't the energy expended be below the lower graph?? because the one between the two graphs is recovered?

the one below the lower graph is recovered the energy between two graphs is the energy lost

 

[daredevil]

Heyy
would any of u happen to have complete nuclear physics notes? plz upload them if u can

 

[Tabi Sheikh]

t
the one below the lower graph is recovered the energy between two graphs is the energy lost

as the energy is energy lost is the difference between the energy spared and energy recovered

 

[daredevil]

as the energy is energy lost is the difference between the energy spared and energy recovered

oohhh rytt!!
so we will take (energy under both graphs) - (energy ender lower graph) to get (energy b/w the graphs) which will be the energy lost???
is that wat is happening?

 

[Tabi Sheikh]

oohhh rytt!!
so we will take (energy under both graphs) - (energy ender lower graph) to get (energy b/w the graphs) which will be the energy lost???
is that wat is happening?

yeah

 

[daredevil]

yeah

thanks a bunch man!!

 

[megamind]

they can work without the satellite but they can only propagate by line of sight , which means they only travel in a straight line from transmitter to receiver .

I just imagined the signal to attenuate to almost zero power

thanks for getting me out of this illusion

 

[Tabi Sheikh]

thanks a bunch man!!

ur welcome

 

[Shreeram]

Its true that what i also thought but the marks allotted is 3 and the ms says that answer is 9.5m/s^2 thats y i got confused

 

[Soldier313]

Aoa wr wb
Can someone please explain qn 9, the whole of it?

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_qp_4.pdf
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s09_ms_4.pdf

My previous doubts :

Aoa wr wb
Can someone please explain
5 b ii - ?

11 - i don't understand the last phrase in the ms where it says the crystal is cut.

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_42.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_ms_42.pdf

Thank you

 

[daredevil]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
Can u help me with Q4c; Q5a(ii); Q6a; Q6d; and Q7b(ii)

 

[Tabi Sheikh]

Its true that what i also thought but the marks allotted is 3 and the ms says that answer is 9.5m/s^2 thats y i got confused

man just take any two points on graph and you will calculate the gradient it will e 9.5

 

[hiltonhacks]

Guys urgent ... help me a problem

9702/21/O/N/11 question number 4 c (ii)
i don't understand how to find the mass of water per second ??

help pls!!

 

[Tabi Sheikh]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
Can u help me with Q4c; Q5a(ii); Q6a; Q6d; and Q7b(ii)

q4 c) for lower frequency we need a longer wavelength as the speed of sound is constant 330 ms^-1 so the longest wavelength will be 4*45cm =1.8m because large sound is only produced when anti node is formed at the open end of the tube. so the longest wavelength will causes by the fundamental frequency

 

[Tabi Sheikh]

Guys urgent ... help me a problem

9702/21/O/N/11 question number 4 c (ii)
i don't understand how to find the mass of water per second ??

help pls!!

since power = Enrgy /time therefore 0.25* (1/2)*m*v^2/t=110000
110000/(0.5*0.25*15.3^2)=m/t