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Physics: Post your doubts here!

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Q3ii)since there is no accel. therefore log is said to be in equilibrium i.e. not external force acting related with newtons first law
Q3 iii) weight component downward + frictional force equal to tension
Q3 iv) since friction is involved there will be loss of energy due to friction
sorry i did not get ii) o_O how do u work with just adding 2 forces in different directions and not even considering the angle? is that even possible?? o_O
 

asd

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sorry i did not get ii) o_O how do u work with just adding 2 forces in different directions and not even considering the angle? is that even possible?? o_O
He actually meant the component down the slope, he just used the wrong word "downward" :p
 

asd

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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
6b (i) and (ii)
If for the first part we're considering that there will be a short circuit and therefore the ammeter reading is going to be 0, why doesnt the same reason go for the second part? (cause the question says the wire has a negligible resistance)
littlecloud11 , since you seem to be a smart guy -_-
Oh, and gary221

regardless of the resistance of the wire... we r measuring the current which passes thru the wire ---> V = IR (ohm's law)
So, the current passing thru the wire will hv 2 pass thru the ammeter itself which has resistance of ohms.

The reason the reading is 0 in the 1st one is bcoz p.d = 0 (as both the points(A n C) r at the same potential ie A ---> Since V = 0V , so V = IR
I = V/ R
= 0/5
I = o A

Hope u gt it!!
:)
 
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asd

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regardless of the resistance of the wire... we r measuring the current which passes thru the wire ---> V = IR (ohm's law)
So, the current passing thru the wire will hv 2 pass thru the ammeter itself which has resistance of ohms.

The reason the reading is 0 in the 1st one is bcoz p.d = 0 (as both the points(A n C) r at the same potential ie A ---> Since V = 0V , so V = IR
I = V/ R
= 0/5
I = o A

Hope u gt it!!
:)
Umm, why isnt the ammeter in series, firstly? :p
and shouldnt they be at the same potential even if C is connected to B, cause 0 resistance should give 0 p.d?
 

asd

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or are we considering there has to be a p.d between A and B because they're a distance apart, even though its stated the wire has negligible resistance?
 
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Umm, why isnt the ammeter in series, firstly? :p
and shouldnt they be at the same potential even if C is connected to B, cause 0 resistance should give 0 p.d?

its in sries coz its a potentiometer... see txtbk!
 
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asd... no they aren't at the same potential..coz pd (= the energy given up bt unit charge as it moves from pt to pt) n potential B will defn be differnt from potential at A, hence thr is a pd btw the 2 two pts.. if the potential at both the points is same, current will not flow...
 
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asd

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asd... no they aren't at the same potential..coz pd (= the energy given up bt unit charge as it moves from pt to pt) n potential B will defn be differnt from potential at A, hence thr is a pd btw the 2 two pts.. if the potential at both the points is same, current will not flow...
That's exactly what Im saying man. :D
why would the charge give up any energy if there's no resistance in the wire?
And my textbook doesnt say its series :/
Im confused. :(
 
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That's exactly what Im saying man. :D
why would the charge give up any energy if there's no resistance in the wire?
And my textbook doesnt say its series :/
Im confused. :(

nah..it says 'negligible resistance' --->although the resistance is present it is quite small n u shudnt consider it for ur calculations
wht coursbk do u hv??
 
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sorry i did not get ii) o_O how do u work with just adding 2 forces in different directions and not even considering the angle? is that even possible?? o_O
well its weight's component down the slope + frictional force
mathematically
W*sin(12)+frictional force =Tension
 
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