Physics: Post your doubts here!

[daredevil]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_22.pdf

can someone please explain Q5 part b

some one really plz solve this question its a pain in the neck -___-

 

[asd]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_21.pdf 5ci

P has a direction to right, N to the left.
P is positive. You do realize that electric fields go from positive to negative. so to the left of the particle is obv a positive potential.

 

[daredevil]

Physic ATP questions/answers which can gain precious marks for A*

y r u posting atp here??

 

[A star]

P has a direction to right, N to the left.
P is positive. You do realize that electric fields go from positive to negative. so to the left of the particle is obv a positive potential.

rite now all i know is 2+2=6

 

[A star]

y r u posting atp here??

some one really plz solve this question its a pain in the neck -___-

p5 madam

 

[daredevil]

P has a direction to right, N to the left.
P is positive. You do realize that electric fields go from positive to negative. so to the left of the particle is obv a positive potential.

hmmm and we'll calculate the torque by first calculating the perpendicular distance using the angle and the linear distance ryt???

 

[Tabi Sheikh]

AHHH, Youre confusing the resistance at Pd of 4v with resistance at pd of 7v. Check your method mate!

since c and R Are in series the voltage is not same so i assumed that the voltage across the C is 4 V

 

[daredevil]

p5 madam

oohhhh -__- nevvaa mind -__-

 

[asd]

some one really plz solve this question its a pain in the neck -___-

calculate the currents in each loop.
for pd in wire to 40 cm, V= (1.2)(40/100 * 10) = 4.8
for pd in 4 ohm resistor, V = (2)(4) = 8
now difference in potential = 8 -4.8

 

[A star]

some one really plz solve this question its a pain in the neck -___-

here goes nothing
pd across Ac 40/100 * 12 = 4.8
pd across Ad 4/6 * 12 = 8
8-4.8 =3.2

 

[daredevil]

since c and R Are in series the voltage is not same so i assumed that the voltage across the C is 4 V

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

 

[A star]

calculate the currents in each loop.
for pd in wire to 40 cm, V= (1.2)(40/100 * 10) = 4.8
for pd in 4 ohm resistor, V = (2)(4) = 8
now difference in potential = 8 -4.8

beat me by a sec

 

[A star]

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

question kia hae ??????????????????

 

[beewhiz997]

does anyone know how to do q 1(d) paper 2 o/n 11 variant 23???

 

[Tabi Sheikh]

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

u just draw the graph of the resistor then you will get the clear view of it...

 

[asd]

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

Oh, you agree with me. ^_^ ^_-

 

[asd]

beat me by a sec

Dude, Work done by "asd" per unit time is the same as (ten to the power of infinity Newtons)*(speed of light)

 

[mizmoody]

calculate the currents in each loop.
for pd in wire to 40 cm, V= (1.2)(40/100 * 10) = 4.8
for pd in 4 ohm resistor, V = (2)(4) = 8
now difference in potential = 8 -4.8

thank you!

 

[daredevil]

Oh, you agree with me. ^_^ ^_-

do u get wat he is saying about making the graph of resistors? because i don't -__- as far as that graph is given in the question the resistance gradient is way too high now to extend the graph ithink... the graph is almost vertical even before reaching 6V ..... :O

 

[A star]

Dude, Work done by "asd" per unit time is the same as (ten to the power of infinity Newtons)*(speed of light)

and chora times infinite