Physics: Post your doubts here!

[A star]

omigosh.. iwud never have been able to do it without the ms -___- :O

anyways u know that acceleration due togravity is 9.81ms^-2
and acceleration is in the downward direction so it will be 9.81sin15
then apply a formula in which u don't need to put in the final velocity because u don't know it and u can calculate the time simultaneously.
from the three eq of motion the formla we have is:
s=ut + (1/2)at^2

as it is initially at rest so u=0
s=at^2 is the eq u hav
substitute the values and take it from there

see next question -_-

 

[A star]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_21.pdf 5ci

 

[daredevil]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_22.pdf

can someone please explain Q5 part b

some one really plz solve this question its a pain in the neck -___-

 

[asd]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_21.pdf 5ci

P has a direction to right, N to the left.
P is positive. You do realize that electric fields go from positive to negative. so to the left of the particle is obv a positive potential.

 

[daredevil]

Physic ATP questions/answers which can gain precious marks for A*

y r u posting atp here??

 

[A star]

P has a direction to right, N to the left.
P is positive. You do realize that electric fields go from positive to negative. so to the left of the particle is obv a positive potential.

rite now all i know is 2+2=6

 

[A star]

y r u posting atp here??

some one really plz solve this question its a pain in the neck -___-

p5 madam

 

[daredevil]

P has a direction to right, N to the left.
P is positive. You do realize that electric fields go from positive to negative. so to the left of the particle is obv a positive potential.

hmmm and we'll calculate the torque by first calculating the perpendicular distance using the angle and the linear distance ryt???

 

[Tabi Sheikh]

AHHH, Youre confusing the resistance at Pd of 4v with resistance at pd of 7v. Check your method mate!

since c and R Are in series the voltage is not same so i assumed that the voltage across the C is 4 V

 

[daredevil]

p5 madam

oohhhh -__- nevvaa mind -__-

 

[asd]

some one really plz solve this question its a pain in the neck -___-

calculate the currents in each loop.
for pd in wire to 40 cm, V= (1.2)(40/100 * 10) = 4.8
for pd in 4 ohm resistor, V = (2)(4) = 8
now difference in potential = 8 -4.8

 

[A star]

some one really plz solve this question its a pain in the neck -___-

here goes nothing
pd across Ac 40/100 * 12 = 4.8
pd across Ad 4/6 * 12 = 8
8-4.8 =3.2

 

[daredevil]

since c and R Are in series the voltage is not same so i assumed that the voltage across the C is 4 V

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

 

[A star]

calculate the currents in each loop.
for pd in wire to 40 cm, V= (1.2)(40/100 * 10) = 4.8
for pd in 4 ohm resistor, V = (2)(4) = 8
now difference in potential = 8 -4.8

beat me by a sec

 

[A star]

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

question kia hae ??????????????????

 

[beewhiz997]

does anyone know how to do q 1(d) paper 2 o/n 11 variant 23???

 

[Tabi Sheikh]

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

u just draw the graph of the resistor then you will get the clear view of it...

 

[asd]

really i agree with asd.... how u assume that?? i mean if u were given the resistances of both the resistors here u could use the ratio method and all but how can u ASSUME here??

Oh, you agree with me. ^_^ ^_-

 

[asd]

beat me by a sec

Dude, Work done by "asd" per unit time is the same as (ten to the power of infinity Newtons)*(speed of light)

 

[mizmoody]

calculate the currents in each loop.
for pd in wire to 40 cm, V= (1.2)(40/100 * 10) = 4.8
for pd in 4 ohm resistor, V = (2)(4) = 8
now difference in potential = 8 -4.8

thank you!