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Physics: Post your doubts here!

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guys i have a good news to all i have seen that this paper in niv timetable was easy and had alot of gaps so is hard to our paper will probably be easy :D
 
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2(b)(ii) seperation of atoms in the cube, V = r^3
r = (1.8x10^-23)^1/3 = 2.6x10^-8 cm

4(c)(ii) 1. Change in Ep = mg(changein h)
= 3.8 x (0.178-0.163) = - 0.057 (-ve since potential energy decreases)

2. Change in elastic P.E = 0.5k( x2^2 - x1^2)
= 0.5x180( 0.036^2 - 0.021^2)
= 0.077 J

(c)(ii) It is the speed of either one of the progressive waves travelling along oppsite directions that have superposed to form the stationary wave after the wave has been reflected at P

Hope this helps !
i didn't get 2bii
wat u did was find the radius ... how does it give us the separation between 2 atoms like if these are 2 atoms:
O--O


we need to find the dotted line part ryt? how does the radius giv us that?
 
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guys i have a good news to all i have seen that this paper in niv timetable was easy and had alot of gaps so is hard to our paper will probably be easy :D
yeah i think that is y we are getting halwa papers this far bcz of the no holz in btween situation.. ooh stats is gonna make us feel like a chimp in the CAR?.... wat u said :p X|
 
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i'll check out ur question but meanwhile can u tell me that in Q6 bii of the same paper why can't we use the formula v=s/t ??
umm basically you cant because since the stupid electron is accelerating velocity aint constant is it?
 
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yeah i think that is y we are getting halwa papers this far bcz of the no holz in btween situation.. ooh stats is gonna make us feel like a chimp in the CAR?.... wat u said :p X|
haha i was thinking the same thing xD and now p1 will be a horror to behold
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w09_qp_22.pdf

okaays
plz explain to me
Q2b(ii) 2.
Q4cii
Q5 a(ii); b; c(ii)

of this paper and explain the answers too plzzz

2b(ii)2.
umm you found out that the volume occupied by each atom is 1.8x 10^-23
so since volume is l^3 (l here being the diameter, though volume of a sphere isnt l^3 anyways,) so length is cube-root of volume

Q4cii
p.e = m.g.(change in)h
3.8 x (0.178-0.163)
0.057 J

the other parts im still trying to get..
 
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2b(ii)2.
umm you found out that the volume occupied by each atom is 1.8x 10^-23
so since volume is l^3 (l here being the diameter, though volume of a sphere isnt l^3 anyways,) so length is cube-root of volume

Q4cii
p.e = m.g.(change in)h
3.8 x (0.178-0.163)
0.057 J

the other parts im still trying to get..
lmfao i ws seeing the wrong ms and was stupified how to use resistance to find volume xD
 
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2b(ii)2.
umm you found out that the volume occupied by each atom is 1.8x 10^-23
so since volume is l^3 (l here being the diameter, though volume of a sphere isnt l^3 anyways,) so length is cube-root of volume

Q4cii
p.e = m.g.(change in)h
3.8 x (0.178-0.163)
0.057 J

the other parts im still trying to get..
in 4eii weight is also changing y havent u considered that??? its going from being 3.8 to being 6.48 .... tabhi to extension hcange hui hai na!! :O
 
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