- Messages
- 28
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Umm.. Question no 7? plzz..Well I don't get the question myself :/
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Umm.. Question no 7? plzz..Well I don't get the question myself :/
Cambridge should be sued for such questionsLol Nevermind..
Thankss
How do u know my name? :O well only 6 papers
konsa mein batoon?Cambridge should be sued for such questions
Cambridge should be sued for such questions
The answer is C cuz the area which is to displacement is a trapezium hence area of trapezium is half into height into sum of parallel sides hence area is 0.5 into 2 into (6+12)=18...I hope this is rightUmm.. Question no 7? plzz..
The answer is C cuz the area which is to displacement is a trapezium hence area of trapezium is half into height into sum of parallel sides hence area is 0.5 into 2 into (6+12)=18...I hope this is right
klkonsa mein batoon?
Octnov.09 v.11 q7Umm.. Question no 7? plzz..
Octnov.09 v.11 q7[/qu anooshay tm ne sahi kiya hai
Applying f=ma, -60=30*a...hence a=-2....now applying s=ut plus half at square....s=3*.5+.5*-2*0.5square=1.25m.....yeah that's right!
q 10?
How? Explain the logic...
How? Explain the logic...
Oh sorry please explain q9tm ne sahi kiya hai
i need to go mein ne abhi tk sirf 2011 tak kiye hain
Oh sorry please explain q9
Well I got it D
When the question mentions it is an elastic collision that means kinetic energy is conserved (means initial KE= final KE)
so just check o all the options which one satisies the condition
the answer is A!
Thank you so much
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