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Physics: Post your doubts here!

sma786

sma786

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What are Piezo-Electric Transducers basically? What do they do?
Do they convert The energy of the positive and negative ions to Voltage or whaT?
 
Dashexdan

Dashexdan

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sma786 said:
Just five months left for my papers, why would i take up bio or chem now? :p
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ummm 5, 6 months are kinda enuf if to study one subject properly bu tusions and all, becz then u wud have 3 subjects in ur alevels and it wud be easier to apply for a variety of degrees :p
 
sma786

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Dashexdan said:
ummm 5, 6 months are kinda enuf if to study one subject properly bu tusions and all, becz then u wud have 3 subjects in ur alevels and it wud be easier to apply for a variety of degrees :p
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I just want an A Level degree, then i am into English Literature and Fashion Designing ;)
 
Dashexdan

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sma786 said:
I just want an A Level degree, then i am into English Literature and Fashion Designing ;)
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ok then its great, u can have two subjects :D btw u shud check these degree requirements in the uni in which u are thinking of applying :D
 
Suchal Riaz

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Can anyone tell me redspot has past papers of which board.
These questions in redspot are not CIE A level past paper questions. I can't find any.
 
hino

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daredevil said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_4.pdf

see question 1 b please!!
in thhe marking scheme it says that frictional force = centripetal force
how ?? i dont get it??
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frictional force=centripetal force since friction provides the centripetal force
For example suppose that a driver of a car makes a sharp turn to the left of a road or u can say a turn about at constant speed. During the turn, the car travels in a circular-type path. That is, the car sweeps out one-quarter of a circle. The friction force acting upon the turned wheels of the car causes an unbalanced force upon the car and a subsequent acceleration. The unbalanced force and the acceleration are both directed towards the center of the circle thus making the car adopt a circular path.So as u can see its the friction thats causing the car to move in circular path meaning its providing the centripetal force.IF IT werent for friction the car wouldnt have been able to make a turn and would have gone straight.
SSupposeuppose
 
daredevil

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hino said:
frictional force=centripetal force since friction provides the centripetal force
For example suppose that a driver of a car makes a sharp turn to the left of a road or u can say a turn about at constant speed. During the turn, the car travels in a circular-type path. That is, the car sweeps out one-quarter of a circle. The friction force acting upon the turned wheels of the car causes an unbalanced force upon the car and a subsequent acceleration. The unbalanced force and the acceleration are both directed towards the center of the circle thus making the car adopt a circular path.So as u can see its the friction thats causing the car to move in circular path meaning its providing the centripetal force.IF IT werent for friction the car wouldnt have been able to make a turn and would have gone straight.
SSupposeuppose
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ooohhh okaaayy thankkss alot!! :) (Y)
plzzz c if u can clear the other querries as well!!
 
Suchal Riaz

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Please help me. I have attached question, answer and examiners comment for your ease.

image.jpg
Answer is A.
Examiner report says "Even many good candidates tried using 90% of atmospheric pressure and had the answer B. This illustrates the problem with algebraic answers. Perhaps if they had realised that their answer was giving a straw of length 9 metres they might have re-checked their answer."
s03qp1q20
 
snowbrood

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Suchal Riaz said:
Please help me. I have attached question, answer and examiners comment for your ease.

View attachment 33317
Answer is A.
Examiner report says "Even many good candidates tried using 90% of atmospheric pressure and had the answer B. This illustrates the problem with algebraic answers. Perhaps if they had realised that their answer was giving a straw of length 9 metres they might have re-checked their answer."
s03qp1q20
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ok so the forces must be acting in equilibrium
upward forces= downward forces
f=P*A P is the atmospheric pressure
atmosphere is pushing the liquid upwards the weight of the liquid and reduced pressure is acting downwards
P*A=(0.9*P*A)+mg
mg=0.1P*A
mass of liquid is density*volume=p" *A*L where p" is density of liquid
p"ALg=0.1*P*A
cancel As on both sides
(P'')*L*g=0.1P
L=0.1P/(p"*g)
 
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