- Messages
- 45
- Reaction score
- 9
- Points
- 18
may june 07 p1 mcq 18,and mcq 10..explain why in mcq 18 option D is incorrect....and why in mcq 10 D is is correct...
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
link please..may june 07 p1 mcq 18,and mcq 10..explain why in mcq 18 option D is incorrect....and why in mcq 10 D is is correct...
I havent studied syallabus relating to mcq 18 so cant explain it,however the answer to mcq 10 is B not D.may june 07 p1 mcq 18,and mcq 10..explain why in mcq 18 option D is incorrect....and why in mcq 10 D is is correct...
I havent studied syallabus relating to mcq 18 so cant explain it,however the answer to mcq 10 is B not D.
link please..
may june 07 p1 mcq 18,and mcq 10..explain why in mcq 18 option D is incorrect....and why in mcq 10 D is is correct...
15)http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_s09_qp_1.pdf
Help with No 15 and No 18 please?
15)
Two ways to look at problem.
The top half of the water on the left fell to the other side. The essence of solving this problem is to remember that the position and motion of any mass can be reduced to that of its centre of gravity.
The centre of gravity of the top half of the water is 1/4 h above the bottom half. When it falls to the other side the centre is now 1/4 h above the bottom. So the centre of gravity fell 1/2h. Since 1/2 of the mass fell 1/2 h the loss of gpe is 1/2h X 1/2 mass X g or 1/4mgh.
Alternatively consider that at the start the centre of mass of the entire mass is 1/2 h above the bottom. Afterwards it is 1/4h above the bottom. So this is the same as the entire mass falling 1/4 h so loss of gpe is 1/4h X mass X g.
18)
For manometers it is the difference in height between the two sides that is a measure of the pressure difference not just how much they move from the position when the pressure on the two sides are the same. Since the side on the right moved up h the side on the left moved down h. The difference in the two levels is 2h so the pressure difference is given by D.
The rotating blades of a hovering helicopter sweep out an area of radius 4.0 m imparting a downward velocity of 12 m/s to the air displaced. Find the mass of the helicopter.(density of air = 1.3 kg/m^3)?
Answer:
(9.4 x 10^2 kg)
Thank you!The weight of the helicopter must equal the downward force of the blades on air. So we need to calculate the force of the blades on air. We cannot use F = ma because we do not have acceleration and cannot calculate it from the information given in the problem. So we use instead F=rate of change of momentum where we assume that a mass of air equal to that of a cylinder with radius of 4 m and height of 12 m is given a velocity of 12 m/s every second.
(4^2 X pi X 12 X1.3) X12 = 9409 N. Now for this problem g = 10.0 and mass is equal to 9.4 X 10^2.
For reasons that I have not yet been able to figure out if you use the formula P = Fv assuming that the same mass is given a velocity of 12m/s every second and calculate power based on the resultant K.E you get one half the value. However in these types of problems momentum rules.
AoA!Thank you!
Find the force exerted on each square meter of a wall which is at right angle to a wind blowing at 20 m/s. assuming that the air does not rebound. (density of air = 1.3 kg/m^3)? (5.2 x 102 N)
The rotating blades of a hovering helicopter sweep out an area of radius 4.0 m imparting a downward velocity of 12 m/s to the air displaced. Find the mass of the helicopter.(density of air = 1.3 kg/m^3)?
Why would they stick together? They're moving in opposite directions. If you imagine 2 snooker balls hitting each other, both of them would rebound in the direction opposite to what they initially had.http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_12.pdf
In MCQ 8, why is option D incorrect? Why don't the spheres stick together after impact?
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w09_qp_12.pdf
In MCQ 8, why is option D incorrect? Why don't the spheres stick together after impact?
...Oh, I didn't read the last part of the question. But anyway, would my reasoning be wrong?" When two objects collide and stick together, the collision is inelastic (perfectly inelastic is the term)." This is why D option is incorrect. As simple as that.
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now