Physics: Post your doubts here!

[Hassan Ali Abid]

Exactly! Now what to do!

Then play with ur calculator and the values and try to get the exact ans which is in ms ...

 

[Hassan Ali Abid]

Exactly! Now what to do!

dividing 414.95 by .5579 , only then we can get ans = 743.77 and then round off the value to get 740. *not sure if we can do this or not*

 

[P1O2I3U4]

Then play with ur calculator and the values and try to get the exact ans which is in ms ...

Oh God!!
Okay what about the other question i asked!
And thanks a lot for your help

 

[P1O2I3U4]

dividing 414.95 by .5579 , only then we can get ans = 743.77 and then round off the value to get 740. *not sure if we can do this or not*

Yeah!! But we won't know what is the right answer in the exam so...

 

[Hassan Ali Abid]

Yeah!! But we won't know what is the right answer in the exam so...

exactly we wont know but if we the procedure is valid and the ans is correct then they have to award the marks for that ...

 

[Hassan Ali Abid]

fantastic girl

 

[P1O2I3U4]

exactly we wont know but if we the procedure is valid and the ans is correct then they have to award the marks for that ...

Have you seen the procedure in the mark scheme? I don't understand a word!

 

[Hassan Ali Abid]

Have you seen the procedure in the mark scheme? I don't understand a word!

I didnt check that ...Ia i'll see it tomorrow ...now i wont spare this idiot question

 

[P1O2I3U4]

I didnt check that ...Ia i'll see it tomorrow ...now i wont spare this idiot question

Thanks

 

[Hassan Ali Abid]

Thanks

np

 

[snowbrood]

Have you seen the procedure in the mark scheme? I don't understand a word!

using the same formula first calculate the number of moles of gas filled in each balloon ...ryt ...
then ____ moles of gas : 1 ballons (number of balloons)
_______moles calculated in part b(1):x and by this calculate the total number of balloons.

calculate like this and see if the ans is ryt or not.

find the number of moles of hydrogen that one balloon contains using the equation PV=nRT u will get n=0.56
one balloon 0.56moles
x no of balloons 415moles
calculate x u will get 741

 

[usama321]

salams,
so i've got 2 questions that need checking.
I will provide everything, you just need to read.

1st question
It's about forces
View attachment 36895

The answer
View attachment 36897

And the other question and answer.

View attachment 36898

Thanks in advance.

For the first question, there is no work done in moving an object horizontally in air, so the work done is only against gravity, that is while moving the object vertically... so F* vertichal heigh = 20 kJ

For the second question, you have to keep in mind that velocity is a vector. Thus when it bounces of, it is in the opposite direction and the velocity you will use in your calculation will be -12.2... so

1/2 *.2 * (15.8^2 - (-12.2) ^2)

 

[papajohn]

For physics and chemistry, How many correct to significant figure do we have write answer?

 

[Hassan Ali Abid]

For physics and chemistry, How many correct to significant figure do we have write answer?

3sf

 

[papajohn]

Please can anyone solve me the question of Pacific book Volume 2 self evaluation 10.7 page no 278 Q:3. I tried very hard but cant solve it. Even the electrical engineer whom i give to solve cant solve it.

 

[sara kamal]

Please tell me how to calculate absolute errors when lg is present...where for eg R is 2+-0.2 and lgR is 0.3,whats erroe with 0.3??
i will be very thankful!

 

[Hassan Ali Abid]

Please tell me how to calculate absolute errors when lg is present...where for eg R is 2+-0.2 and lgR is 0.3,whats erroe with 0.3??
i will be very thankful!

Lg 2.2-Lg2.0 = error
Thats the way to calculate all the errors ..

 

[mm89mm]

For the first question, there is no work done in moving an object horizontally in air, so the work done is only against gravity, that is while moving the object vertically... so F* vertichal heigh = 20 kJ

For the second question, you have to keep in mind that velocity is a vector. Thus when it bounces of, it is in the opposite direction and the velocity you will use in your calculation will be -12.2... so

1/2 *.2 * (15.8^2 - (-12.2) ^2)

I didn't understand the vertical height = 20kJ and how is it possible that there is no work done while in the air in the horizontal direction?, would you please explain better if dont mind? And thanks for the reply,

 

[sara kamal]

Lg 2.2-Lg2.0 = error
Thats the way to calculate all the errors ..

Jazak Allah khair..!

 

[ahmed abdulla]

Can someone help with :
Question 6 (c)
& Question 12 (c)