• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
115
Reaction score
56
Points
38
A2 physics topical questions !!!! :):)
 

Attachments

  • AC.pdf
    226.4 KB · Views: 5
  • Circular.pdf
    681.7 KB · Views: 5
  • Magnetism.pdf
    1 MB · Views: 3
  • Electro-Statics.pdf
    707.1 KB · Views: 4
  • Nuclear.pdf
    448.9 KB · Views: 6
  • Oscillations.pdf
    817.4 KB · Views: 3
  • Qunatum.pdf
    391.9 KB · Views: 4
  • Thermodynamics.pdf
    797.8 KB · Views: 3
Messages
122
Reaction score
93
Points
38
hi i have a tiny doubt it the latest p2 paper
ques #2 part (a)
why have they done 0.8 x 10^-6 instead of 0.8 x 10^-3? ( aren't we supposed to convert from cm to m? or am i missing something :X3:)
 

Attachments

  • 9702_w13_ms_23.pdf
    116.2 KB · Views: 3
  • 9702_w13_qp_22.pdf
    259.8 KB · Views: 8
Messages
1,412
Reaction score
6,320
Points
523
hi i have a tiny doubt it the latest p2 paper
ques #2 part (a)
why have they done 0.8 x 10^-6 instead of 0.8 x 10^-3? ( aren't we supposed to convert from cm to m? or am i missing something :X3:)

the time taken by the pulse to travel whole distance is o.8 micro sec... or o.8 x 10^-6...
time taken to reach the reflector is o.4 micro sec
so d=3x10^8 x 0.4x10^-6 = 240 m ...
we wont convert cm into m ... cz the calibration and the time... both use cm... and cm will be cancelled while calculating time
1 cm= 0.2 micro sec
4 cm= 0.8 micro sec
 
Messages
94
Reaction score
66
Points
28
formulas u will have to use..
attenuation=10 x log(P in/P out)
signal to noise ratio=10 x log (P out/P noise)
attenuation per uni length=total att/total lenth

do as follow
1 find power out......using secong formula.. 30=10 x log(p out/6.5x10-6) so p out=6.5x10-3W
2.find attenuation using formula 1 att=1o x log(26x10-3/6.5x10-3) so attenuation=6.02dB
3 finally find length using formula 3 length= 6.02/0.2=30 km
 
Messages
253
Reaction score
1,195
Points
153
formulas u will have to use..
attenuation=10 x log(P in/P out)
signal to noise ratio=10 x log (P out/P noise)
attenuation per uni length=total att/total lenth

do as follow
1 find power out......using secong formula.. 30=10 x log(p out/6.5x10-6) so p out=6.5x10-3W
2.find attenuation using formula 1 att=1o x log(26x10-3/6.5x10-3) so attenuation=6.02dB
3 finally find length using formula 3 length= 6.02/0.2=30 km
for the 1st step the formula ok is understood then u make pout the subject then wht has to be done i dont get then how to get it plz elaborately explain the first step
 
Messages
2,332
Reaction score
9,506
Points
523
Didn't know there were 'speaking rules' here,
And really, I'd think people in this thread would have grown up with less sensitivity.
:whistle:
Oh please. Thers something called manners Miss sma786. And people are surely grown up here with quiet a lot og good manners. They have some respect. Some self respect. Try to speak with respect with the opposite gender.
 
Top