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Help needed.
For the first image (the potential energy question):
Let's first try to find out whether the potential energy of the system increases or decreases:
The field shown can either correspond to a large, positively charged sheet on the left side of the image, or a large, negatively charged sheet on the right side of the image.
Since the charge is a positive charge, moving it to the left would bring it closer to the positive sheet and farther away from the negative sheet.
Note that just as we ignore the change in potential energy of the Earth when an object falls from a height (because that change is so small compared to the change in PE of the falling object), we ignore the change in potential energy of the charges producing the field, since that change is minuscule compared to the change in potential energy of the single charge. Therefore, the potential energy of the charge is in reality the potential energy of the charge + the potential energy of the system of charges that produce the field.
Since the force on the charge is to the right and will accelerate it in that direction, if we need to keep it's kinetic energy constant (i.e. keeping it's velocity constant, since mass remains unchanged), we need to apply a force to the left (if we applied a force to the right, then it would accelerate in that direction). Also note that the forces are all constant in magnitude since the field lines are equally spaced apart all the time, and so the electric force and the mechanical force involved remain the same.
So, if the force we apply is to the left, and the displacement is towards the right, and the kinetic energy remains constant, where does the work done by the force go?
The answer is simple: since the force does negative work, the internal forces of the system (where the system consists of the positive charge AND the charges producing the field) must do positive work, and thus they transfer energy OUT of the system. Therefore, the internal electric potential energy decreases when the charge is moved from X to Y.
Now to figure out how much the change is, i.e. the magnitude of the change. Since the kinetic energy of the system remains constant, the work done by all the forces adds up to zero. In other words,
(Work done by mechanical force) = (Work done by electric force) = (Decrease of Internal Energy of the system)
Therefore, using the dot product, we can say that the work done by the electric force in moving the charge from X to Y = F * r * cos(theta) = F * r * (s/r) - Fs
Therefore, the internal energy decreases by Fs = A.
For the second question, we can work with the fact that both wires are made of the same material, have the same length, and thus they will have the same resistivity (since resistivity is a property of the material, not the dimensions of the sample concerned).
Therefore, taking the formula for resistivity as ρ = RA/l ,
R(P) =R(Q) * A(Q)/A(P)
The Cross Sectional Area of Q= (pi) * (0.0005)^2 = A(Q)
The Cross Sectional Area of P =(pi) * (0.001)^2 = A(P)
So, taking these values, A(Q)/A(P) is equal to 0.25 = 1/4
Therefore, R(P) = R(Q)/4
Since the potential difference across the ends of the wires are equal and I = V/R,
I(P)/I(Q) = R(Q)/R(P) = 4/1 = D.
Hope this helped!
Best of luck for all your exams!