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Physics: Post your doubts here!

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As CB also has resistance, just think of it as another resister in series with the two parallel resistors. now if the emf of the batter is 6v (dont remember the question), some of the voltage would be dissipated across the CB resistor first, and the rest of 6v is then equally dissipated across the two parallel resistors

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I see, so you treat AC as if it's resistors combined in parallel?

And voltage dissipated across CB first? despite the direction conventional current?
 
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I see, so you treat AC as if it's resistors combined in parallel?

And voltage dissipated across CB first? despite the direction conventional current?
Not dissipated first. But not all is equally distributed across the parallel wires. Some is left and dissipated across CB
 
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naee i mean kin formulas say derive kiya hai?? o_O like KAI VALUES KO DEKH KAI KHUD m/s nikala hai!!? :p
It's kg/s. And khud try ker k nikala hai :p Though search it online, zarur hoga.. Kg/m^3 *m/s = kg/m^2 s.This means, one kg per second per m^2 of area. Just multiply with the number of m^2 (area) you have and you get kg/s on that specified area.
 
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