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Physics: Post your doubts here!

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if you have casio fx 991ES or other good calculator here is how to do this:
press mode press 4
now write a decimal number, lets say 125 and press =
now press shift+log
it will show the binary as 000000001111101
all you need it 11111101
 
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Need this answers with a little explanation please
001.jpg

 
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2) A and D must not be the answer, Its obvious.
the answer is C. because unit current is not like unit charge.
current is how many electrons in a second i.e. e/second, which has Amps as its unit.
Charge is Coulomb with a unit C. so both of them are NOT the same.
p.d.= work done/unit charge NOT work done/current SO Answer is not B

7) 20) Suchal Riaz ZaqZainab

31) Before we select an answer, let's review what each answer means.

A. The mathematical expression of this statement is F = E*q. Voltage (potential difference) is not a force, and the E here is an electric field not a difference in potential, so this answer cannot be correct.

B. Energy = V*q = d*E*q is the mathematical expression referred to here. Since I (current) = dq/dt, q = I*t (current is the derivative of charge with respect to time, thus total charge is current times total time passed). This means Energy = V*q (voltage times charge) = V*I*t (voltage times average current times time elapsed), which can be rearranged to say V = E/(I*t). This is not the ratio of energy to current, rather the ratio of energy to charge passed, so this answer cannot be correct.

C. Power = V*I. Thus V = P/I. This is a correct assessment of potential difference. Saying that potential difference in a wire is equal to the ratio of power to current is correct, since V = P/I, so this answer is acceptible.

D. P = V*I = V*dq/dt, which means V = P/(dq/dt). You can go one step further and integrate the top and bottom of this equation and say V = int(dE/dt)/int(dq/dt) = E/q. In neither case is the potential difference the ratio of power to charge moved, it is either the ratio of power to charge moved per second (current), or it is the ratio of the energy dissipated to the charge moved. So this answer is unacceptible.

Thus the answer is C.
 
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2) A and D must not be the answer, Its obvious.
the answer is C. because unit current is not like unit charge.
current is how many electrons in a second i.e. e/second, which has Amps as its unit.
Charge is Coulomb with a unit C. so both of them are NOT the same.
p.d.= work done/unit charge NOT work done/current SO Answer is not B

7) 20) Suchal Riaz ZaqZainab

31) Before we select an answer, let's review what each answer means.

A. The mathematical expression of this statement is F = E*q. Voltage (potential difference) is not a force, and the E here is an electric field not a difference in potential, so this answer cannot be correct.

B. Energy = V*q = d*E*q is the mathematical expression referred to here. Since I (current) = dq/dt, q = I*t (current is the derivative of charge with respect to time, thus total charge is current times total time passed). This means Energy = V*q (voltage times charge) = V*I*t (voltage times average current times time elapsed), which can be rearranged to say V = E/(I*t). This is not the ratio of energy to current, rather the ratio of energy to charge passed, so this answer cannot be correct.

C. Power = V*I. Thus V = P/I. This is a correct assessment of potential difference. Saying that potential difference in a wire is equal to the ratio of power to current is correct, since V = P/I, so this answer is acceptible.

D. P = V*I = V*dq/dt, which means V = P/(dq/dt). You can go one step further and integrate the top and bottom of this equation and say V = int(dE/dt)/int(dq/dt) = E/q. In neither case is the potential difference the ratio of power to charge moved, it is either the ratio of power to charge moved per second (current), or it is the ratio of the energy dissipated to the charge moved. So this answer is unacceptible.

Thus the answer is C.

thanks and in mcq 2 y is it obvious that A and D r incorrect?
 
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