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I'm using x to denote the intensity of the emerging light.
I/x = a^2/(a cos 60*)^2
=> 1/x = a^2/ 0.25 a^2
So, x = 0.250 I.
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I'm using x to denote the intensity of the emerging light.
Highlighted part: work done against friction = frictional force x distance moved due to friction (which is up the slope).Can you please explain the highlighted part? Thank You
see Kr has half life of 3 s.....there are two ways....one that u can set up an equation but thats more error prone so better off stick with the second method.........that after 1st 3 s Kr wd be 1/2.....after another 3 s it wud be 1/4th ......and after another 3 it wud be 1/8th whereas because of comparatively very big half life of Ba.....it wud decay be very small amount so after approx. 9 sec rattio will become 8http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w07_qp_4.pdf
can smbody explain q7 part c to me please!!
14 D as the resultant together with other forces should originate from the same point. it should be springing outwards n upward direction. we can't show dat on a ppr so D looks appropriate in this case i guess.Asalam-o-alaikum
Can you please help with these physics paper 1 questions?
Questions 13, 14, 16, 25, and 33. Thank you very very much.
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s05_qp_1.pdf
Please help me with these?
i didnt get it???? actually i didnt understand the QUestion statement!! pls if u could helppsee Kr has half life of 3 s.....there are two ways....one that u can set up an equation but thats more error prone so better off stick with the second method.........that after 1st 3 s Kr wd be 1/2.....after another 3 s it wud be 1/4th ......and after another 3 it wud be 1/8th whereas because of comparatively very big half life of Ba.....it wud decay be very small amount so after approx. 9 sec rattio will become 8
@OMG i Wanted to ask about an upper part of this question that why is fission energetically feasible......so ms was saying greater binding energy of products compared with reactants....bt how does it explain the energitcally feasible thing
i didnt get it???? actually i didnt understand the QUestion statement!! pls if u could helpp
thankyou so much@ OMG
in the question the time is asked for the ratio of undecayed nuclie of Ba /Kr
we know that the no. of undecayed nuclie could be found out by the formula of N = N0e^-lmda.t
now it is given that the ratio of N(BA)/N(Kr) =8 means that N0e^-lmda(Ba).t /N0e^-lmda(Kr).t = 8
now simplify the equation u will get e^- lmda.t/e^-lmda.t as the N0 is cancelled at both sides and lmda and T both are having different values for Ba and Kr will remain as they are
from the given eq. find the value of lamda of Ba and lamda of Kr. from this frmula [lmda= ln2/t0.5
puit it into the remainng eq. u will get the value of T
this value is the time for the nuclie to come atthe situation where the ratio of BA/Kr is 8
did u gt it??? if nt let me know! i will make it even better and easier[/quote]
aoa wr wb!how will i determine the frequency of unmodulated carrier wave
thankyou so much
i have one other qs too :/ ?
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