Physics: Post your doubts here!

[farhan143]

I have doubt in b(i) i dont know where to draw and how??

Plzz explain me and show me ur diagram where u've drawn
THANK YOU in advance

 

[farhan143]

i have another doubt it is 4rm 2004 may/june paper 2 Q1_b


the drawing part is my weakness
i dont know where to draw the two lines can anyone draw the diagram and post it back thank you!

 

[farhan143]

plzzzz someone clear doubts!

 

[farhan143]

another doubt !!!!

 

[farhan143]

HHHEEEEELPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

 

[Nibz]

another doubt !!!!
View attachment 4630

(i) Use F = ma
a= 4.5 - 3.5/0.14 (Change in speed) / time
acceleration comes out as 57.1 ms^2
F = (35/1000) * 57.1
F = 1.998
F ~ 2 N

(ii) Loss in kinetic Energy = 1/2 * (35/1000)(4.5^2 - 3.5^2) OR Initial K.E = 1/2 * (35/1000) * 4.5^2 and Final K.E = 1/2 * (35/1000) * (3.5)^2

= 0.14J

(c) There is loss of kinetic energy; the collision of the ball with the plate is inelastic. The loss of momentum during the impact is gained by the plate. So the overall momentum is constant i.e linear momentum is conserved.

 

[unique840]

I have doubt in b(i) i dont know where to draw and how??
View attachment 4608
Plzz explain me and show me ur diagram where u've drawn
THANK YOU in advance

straight line passing through the origin. V=IR. resistance of resistor is constant so V is directly proportional to I

 

[Nibz]

i have another doubt it is 4rm 2004 may/june paper 2 Q1_b
View attachment 4627

the drawing part is my weakness
i dont know where to draw the two lines can anyone draw the diagram and post it back thank you!

I've already solved this question before. Search this thread.

 

[farhan143]

I've already solved this question before. Search this thread.

can u give me the page no.
thank you

 

[Nibz]

can u give me the page no.
thank you

Here: http://xtremepapers.com/community/threads/physics-post-your-doubts-here.9860/page-19#post-131995

 

[123456788]

can anyone please explain and answer
mayjune 2007 number 2 part d
paper-2

 

[farhan143]

Here's the solution:

Thank you so much !!
such a relief....

 

[farhan143]

Doubt in :
Question no 4(d) vector diagram 2007 may/june., paper 2

 

[rz123]

Doubt in :
Question no 4(d) vector diagram 2007 may/june., paper 2

hi, i think it will be done like this : horizontal component of velocity and vertical component of velocity are perpendicular to each other. choose a scale like 1 cm represent 5 m/s. draw a horizontal line indicating horizontal velocity similarly draw a vertical line indicating vertical velocity which is 25.3 m/s. in order to draw the resultant u need to apply parallelogram method or triangle rule. clear?

 

[leadingguy]

use simple formulas and definations here which u can easily fing on aplication support booklet page 22 here is the link
http://www.xtremepapers.com/CIE/ind...ysics/&file=9702 Applications Booklet WEB.pdf

 

[ABDSyed]

Plz Can anyone help me with M/J2005 P1 Q4
I am getting uncertainty 2.25% but the answer Say its 0.4%

 

[leadingguy]

Plz Can anyone help me with M/J2005 P1 Q4
I am getting uncertainty 2.25% but the answer Say its 0.4%

itx simple bro.
v=s/t so v= 16.oms-1 (we will not take 16.00ms-1 as the speed bcz the value of distance is till one significant figure)

now to calculate uncertainity in speed

delta v/V = [delta d/d + delta t/t ]

delta v/V = [0.1/40 + 0.05/2.50]

delta v/V = [9/400]
now dlta v = (9/400) * V ......................... (9/400)*16 = 0.36

remember that distance is till one decimal place so we wil convrt our all ans to one decimal place so rond of 0.36 to 0.4


now ur ans is 16.0+- 0.4 ms-1 (a little logical )

 

[JD REBORN]

Q 24 of p1 May June 2008 and Q18 of may june 2009 with proper explanation.

 

[ABDSyed]

itx simple bro.
v=s/t so v= 16.oms-1 (we will not take 16.00ms-1 as the speed bcz the value of distance is till one significant figure)

now to calculate uncertainity in speed

delta v/V = [delta d/d + delta t/t ]

delta v/V = [0.1/40 + 0.05/2.50]

delta v/V = [9/400]
now dlta v = (9/400) * V ......................... (9/400)*16 = 0.36

remember that distance is till one decimal place so we wil convrt our all ans to one decimal place so rond of 0.36 to 0.4


now ur ans is 16.0+- 0.4 ms-1 (a little logical )

THnx Bro

 

[Silent Hunter]

http://www.xtremepapers.com/CIE/ind... Level/9702 - Physics/&file=9702_s07_qp_1.pdf

help needed in Q12 ? Thank you