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hi, i think it will be done like this : horizontal component of velocity and vertical component of velocity are perpendicular to each other. choose a scale like 1 cm represent 5 m/s. draw a horizontal line indicating horizontal velocity similarly draw a vertical line indicating vertical velocity which is 25.3 m/s. in order to draw the resultant u need to apply parallelogram method or triangle rule. clear?Doubt in :
Question no 4(d) vector diagram 2007 may/june., paper 2
Plz Can anyone help me with M/J2005 P1 Q4
I am getting uncertainty 2.25% but the answer Say its 0.4%
THnx Broitx simple bro.
v=s/t so v= 16.oms-1 (we will not take 16.00ms-1 as the speed bcz the value of distance is till one significant figure)
now to calculate uncertainity in speed
delta v/V = [delta d/d + delta t/t ]
delta v/V = [0.1/40 + 0.05/2.50]
delta v/V = [9/400]
now dlta v = (9/400) * V ......................... (9/400)*16 = 0.36
remember that distance is till one decimal place so we wil convrt our all ans to one decimal place so rond of 0.36 to 0.4
now ur ans is 16.0+- 0.4 ms-1 (a little logical )
According to the law of conservationof momentum,
Re: Physics questions? please?
Question 10 Please.
Thanks!
11 is C. Using F=ma, where F is the resultant force So, F would be 10-4 and m would be 20/10=10, substitute these values to find a.
11 is C. Using F=ma, where F is the resultant force So, F would be 10-4 and m would be 20/10=10, substitute these values to find a.
My bad, sorry. You're right. You get the right answer with 6/2=3 don't you?wont 20/10 = 2 ?
Is the answer A?
Is the answer A?
first of all regarding no. 11 f=ma the weight of the substance is 20kg an its mass is 2 as g=10 in this case
Total work done= Work done against friction+Work done to increase the Potential Energy
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