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Physics: Post your doubts here!

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Is it important to know how to draw leading and lagging phase difference? Nowadays they just ask phase difference but in 2002 they asked for lagging which I don't really understand.
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_23.pdf

Question 5 c(i) 2.
I'm getting 270 degrees..
But the answer is 135 degrees :$
Please explain. :(

Hello there, first we know that 1 Wavelength = 360 degrees, look at the graph, you'll see that 1 wavelength is 8 blocks.

Blocks between A and B are 3 blocks.

Cross multiply,
360-----> 8 blocks
?----------> 3 blocks


You'll get phase difference between A and B is 135 degrees
 
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Umm umm I cant make out! it must be correct :)

The time period of the stationary wave is 20ms. After 5 ms, it would be a straight horizontal line, drawn on the dotted line. Take a look at this animation and you will understand the logic

Standing_wave_2.gif


usama321 :D
but why would be a straight line after 0.005 s? please can u xplain. thnx
Look at this post.
 
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Hello there, first we know that 1 Wavelength = 360 degrees, look at the graph, you'll see that 1 wavelength is 8 blocks.

Blocks between A and B are 3 blocks.

Cross multiply,
360-----> 8 blocks
?----------> 3 blocks


You'll get phase difference between A and B is 135 degrees
Gotcha! I didn't actually see the graph properly.. I was takin it as 4 blocks.. :p
But thank you!!
Plus we can apply the equation as well right.. (X/wavelength *360)
:)
 
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i got it :D look
the horizontal line given is 7 cm
so scale is 4ms^-1 = 7
so 1 ms^-1 =1.75 cm
vertical velocity is 6.2
draw the resiltant it will be 7.4 :)
do u want me to post the diagram but its not neat :oops:?

Oh thanks a lot (y)
would appreciate if u could post it here or Inbox me :love:
 
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Hello there, for B I)
We know that there is a stationary wave in that tube.
At antinodes which are maximum displacement, the wave pushes the heaps apart.
At nodes which are minimum displacement, the heaps are formed
This forms the dust heaps.

For B Ii)

Look at the figure, you'll see that the distance between 6 heaps is 0.39 meters

We know that this stationary wave's wavelength at these heaps is 2.5 Lambda.
Because it has Compression-Rarefaction-Compression and so on.
One wavelength is from C to C or from R to R.

We know Freuquncy F= 2140 Hz

We know speed of wave equation V= Lambda x F


We need 1 lambda and not 2.5 lambda so we need to convert.

0.39 m-----> 2.5 lambda
? ------------> 1 lambda

It's 0.156 m

So V= 2140 x 0.156=334m/s


Iii)
Stationary waves is formed by interference of incident and reflected waves
the speed is the speed of the incident waves
 
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Hello there, for B I)
We know that there is a stationary wave in that tube.
At antinodes which are maximum displacement, the wave pushes the heaps apart.
At nodes which are minimum displacement, the heaps are formed
This forms the dust heaps.

For B Ii)

Look at the figure, you'll see that the distance between 6 heaps is 0.39 meters

We know that this stationary wave's wavelength at these heaps is 2.5 Lambda.
Because it has Compression-Rarefaction-Compression and so on.
One wavelength is from C to C or from R to R.

We know Freuquncy F= 2140 Hz

We know speed of wave equation V= Lambda x F


We need 1 lambda and not 2.5 lambda so we need to convert.

0.39 m-----> 2.5 lambda
? ------------> 1 lambda

It's 0.156 m

So V= 2140 x 0.156=334m/s


Iii)
Stationary waves is formed by interference of incident and reflected waves
the speed is the speed of the incident waves
Can you explain how did you get the wavelength as 2.5 lambda
 
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