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Physics: Post your doubts here!

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yar the way mohammed salik did it dekho
they have told initial wave have intensity I
and its amplitude is a apply it to formula ._.
So is this correct :¬
1I 1A^(2) ---> (we can write it as 2I 2A^(2) means any value of I will be same as A^(2))
So [a cos (60)]^(2) = 0.25A^(2)
Hence we can write it as 0.25I 0.25A^(2)
 
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No nahi aya ._.
Look In Paper ONE there is Way Called Using Proportionality To Solve Equations..!
When they Say Something Is Directly Proportional.. It Mean if One Double.. i.e It changes By a Factor Of Two.. So other Thing must also Change by Factor of Two..!
So We Know I A^(2).! Now Find Factor by Which Amplitude changes..! It is cos50= 0.5.. it Means Aplitude Changes by 0.5..
Amplitude Changes By Cos 60 ( 0.5)..
So I= (cos 60)^2= 0.25 Or (0.5)^2=0.25 I..!
This is The MOST I COULD EXPLAIN..! Is sey Zyada nahi Ho sakta :p!
Hope You Get it this time :)!
 
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Look In Paper ONE there is Way Called Using Proportionality To Solve Equations..!
When they Say Something Is Directly Proportional.. It Mean if One Double.. i.e It changes By a Factor Of Two.. So other Thing must also Change by Factor of Two..!
So We Know I A^(2).! Now Find Factor by Which Amplitude changes..! It is cos50= 0.5.. it Means Aplitude Changes by 0.5..
Amplitude Changes By Cos 60 ( 0.5)..
So I= (cos 60)^2= 0.25 Or (0.5)^2=0.25 I..!
This is The MOST I COULD EXPLAIN..! Is sey Zyada nahi Ho sakta :p!
Hope You Get it this time :)!
Wohi to maine kia tha.... :/
My method:¬
1I 1A^(2) ---> (we can write it as 2I 2A^(2) means any value of I will be same as A^(2))
So [a cos (60)]^(2) = 0.25A^(2)
Hence we can write it as 0.25I 0.25A^(2)

But amplitude given is acos60 not jus cos60 , I mean when squaring it, you get 0.25a^2 so I would be 0.25a^(2)I, wont it be like this ? :(
 
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Wohi to maine kia tha.... :/
My method:¬
1I 1A^(2) ---> (we can write it as 2I 2A^(2) means any value of I will be same as A^(2))
So [a cos (60)]^(2) = 0.25A^(2)
Hence we can write it as 0.25I 0.25A^(2)

But amplitude given is acos60 not jus cos60 , I mean when squaring it, you get 0.25a^2 so I would be 0.25a^(2)I, wont it be like this ? :(
But what about that a^2 ? :/
 
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