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So is this correct :¬
1I ∝ 1A^(2) ---> (we can write it as 2I ∝ 2A^(2) means any value of I will be same as A^(2))
So [a cos (60)]^(2) = 0.25A^(2)
Hence we can write it as 0.25I ∝ 0.25A^(2)
1I ∝ 1A^(2) ---> (we can write it as 2I ∝ 2A^(2) means any value of I will be same as A^(2))
So [a cos (60)]^(2) = 0.25A^(2)
Hence we can write it as 0.25I ∝ 0.25A^(2)