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Physics: Post your doubts here!
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http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_12.pdf
questions 29,34,36,37,38,39 please!
questions 29,34,36,37,38,39 please!
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Since it is transverse wave, the speed same throughout and displacement varies.The option C about K.E is purely rubbish. While the option D is correct because it is a fact.
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I had solve this question, go few pages back or gimme paper link
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Actually the particle is changing its direction. Thus, from moving downwards to moving upwards, there is a change in direction. I am not sure about the speed here, but the acceleration would be high due to the change in direction, as acceleration has both magnitude and direction
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29)
c = f * λ
We know f = 1 / t
so c = 1 / t * λ
t = λ / c
now it took 3 wavefronts to reach XY to P
so t = 3λ / c
34)
36)
Its obviously D :
As Light intensity increases, its resistace decreases, so as R = V / I , R α V, so As R decreases, V would also decrease across LDR.
37)
current is passing through both lamps so they will glow dimly. dimly because the current will be less as now there are two compared to one light bulbs.
38)
What's hard in this ?
Find resistance in each case
3 would be highest with 0.7Ω
and 1 would be least with 0.4Ω
39)
Theory part maat pucho, chapter parho and then na aye to phucho
Last edited:
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9)
First find the time, using S = Ut + 0.5t^(2) ; S = 1.25 , U = zero, t = ?
That is 1.25= 0.5 x 9.81 x t^(2), t = 0.5 seconds.
Now for the Velocity, we know it equals Displacement / time taken ----> V = 10 / 0.5 = 20 m/s so in this type of question either of 2 quantities are given, we just need to find 3rd and input them all in second eqn to get the final result we are asked.
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V1= 5000/ (5000+5000) x 2 = 1V then V2= 3000/ (3000 + 2000) x 2 = 1.2 so V1 - V2 = -0.2 so C
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i'm sooo sooo sorry i pasted the wrong link x_x i it was supposed to be w12 not s12 ugh!29)
c = f * λ
We know f = 1 / t
so c = 1 / t * λ
t = λ / c
now it took 3 wavefronts to reach XY to P
so t = 3λ / c
34)
View attachment 44703
36)
Its obviously D :
As Light intensity increases, its resistace decreases, so as R = V / I , R α V, so As R decreases, V would also decrease across LDR.
37)
current is passing through both lamps so they will glow dimly. dimly because the current will be less as now there are two compared to one light bulbs.
38)
What's hard in this ?
Find resistance in each case
3 would be highest with 0.7Ω
and 1 would be least with 0.4Ω
39)
Theory part maat pucho, chapter parho and then na aye to phucho
For s12 my doubts are actually 7,10,17,28,30 ( and also 29,34,37 but you already answered them lol) soo sorry!
thnk u
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Please mail @ [email protected] if someone knows about physics p34 ...
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Hey. In physics paper 3 (practical), how do I prove whether a mathematical relationship is supported or not by calculating two values of k? Can anybody help me out here?
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Simple as this:
1)You are asked to find out the %uncertainty of(say x) in the one of the question
2)you are also asked to find two values of k (k1 and k2) in one of the question
Now,
suppose you got %uncertainty of x as 20%. Then you find k1+ 20% of k1 AND k1-20% of k1
This is the range
If your value of k2(found in 2) matches it, THE RELATION IS SATISFIED
in most of the questions, it is satisfied.
I hope this helped!
Good luck. Light and luck bless you!
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Simple as this:
1)You are asked to find out the %uncertainty of(say x) in the one of the question
2)you are also asked to find two values of k (k1 and k2) in one of the question
Now,
suppose you got %uncertainty of x as 20%. Then you find k1+ 20% of k1 AND k1-20% of k1
This is the range
If your value of k2(found in 2) matches it, THE RELATION IS SATISFIED
in most of the questions, it is satisfied.
I hope this helped!
Good luck. Light and luck bless you!
I'm still a little confused.
The part that I don't get is this:
"Now, suppose you got %uncertainty of x as 20%. Then you find k1+ 20% of k1 AND k1-20% of k1
This is the range"