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Speed is v first and then increased to v+(20/100*x)=1.2v
Distance is proportional to square of v when acceleration is same so 1.2^2=1.44x
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Physics: Post your doubts here!
- Thread starter XPFMember
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Distance is proportional to square of v when acceleration is same so 1.2^2=1.44x
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Q9
First find the time, using S = Ut + 0.5t^(2) ; S = 1.25 , U = zero, t = ?
That is 1.25= 0.5 x 9.81 x t^(2), t = 0.5 seconds.
Now for the Velocity, we know it equals Displacement / time taken ----> V = 10 / 0.5 = 20 m/s so in this type of question either of 2 quantities are given, we just need to find 3rd and input them all in second eqn to get the final result we are asked.
Q18
pressure = hdg. But here h is 2h since on one side liquid rises by h and another side liquid falls by h.
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use
s=ut+0.5aT^2 and find accelration as per using T and L and then using this a and putting T as 0.5T solve for s and ans will be B.
hope this will help Bro,easy.
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At point S and P both have highest accelerationCan someone tell me what each of these letters represent coz a lot of questions with the same graphs come inn different papers and I keep getting them wrong plz
and Q wont be zero all the time as it is oscillating.
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20)
Take the leftmost column of liquid.
There is a rule in fluid-statics that "the pressure in a sample of liquid is the same at any vertical height, as long as the fluid at that height is part of the whole."
What that says is that in any single sample of liquid, the pressure at any height is the same. Here, it means that the pressure at the top of the leftmost column (connected to the bulb) is the same as the pressure in the next column on the right at the same depth/height. (Neat info here)
So, take the unbroken fluid column on the left. At the top of the leftmost tube (which exposes the fluid to the pressure of the bulb), the pressure at the surface is simply 16,000 Pascals, because that is the pressure in the bulb and is also the pressure with which the gas pushes on any section of the surface around it. The liquid forms part of this surface, so the pressure on the liquid is also 16,000 Pascals.
Now let's move to the next column on the right, where the liquid column is exposed to pressure P. Where it is exposed to pressure P, the surface faces a pressure of P Pascals. This is to be expected. However, as we descend down the liquid, the pressure increases by (ρgh) at a depth h, and continues decreasing with depth.
When we reach depth h1, we note that this level coincides with the vertical level of the fluid in the leftmost column. The pressure on the right side column is
P + ρgh1, while the pressure on the left hand column is 16,000 Pascals. Since these are equal, we can write
P + ρgh1 = 16,000.
Repeating that calculation on the right side, we get
P + ρgh2 = 8,000
Eliminating P,
16,000 - ρgh1 = 8,000 - ρgh2
13,600 * 9.8 * (h1-h2) = 8000
h1 - h2 = 0.06
So the difference is 0.06 meters = 6 centimeters. The only option that agrees is D.
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14)
(0.35*3*9.81)+(0.1*1.4*9.81=(0.15*6*9.81)+ans
ans=2.8Nm
16)
80*28/100=112/5
112/5 =potential energy
112/5=mgh
112/5=(o.12)(9.81)h
P.Sonly 120 g taken into account as only the arrow has a movement.
17)
mgsinteta*speed=40% of total power mgsinteta=force
force*velocity=power
(total m)(9.81)sin30)==40%
100%=ans
18)
Show me your working, as its easy!
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_12.pdf
q 17! please helppp its simple i know but i m not gettin it!
also q 18 22 25
thanx
q 17! please helppp its simple i know but i m not gettin it!
also q 18 22 25
thanx
Last edited:
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14,15,21, and 31!!
14)
Moment = force times distance from the pivote
----------> F * 2R happens in B
15)
( 10cos30 + 10cos30 ) - 10 = 7.3
21)
17.5 *10^6 = 830*g*h + 1000*g*h
17.5 * 10^6 = 8142.3x + 9810(2000 - x)
17.5 *10^6 = 8142.3x + 19 620 000 - 9810x
-2 120 000= -1667.7x
1271.2 = x
~ 1270 m (3 s.f.)
31)
Use Q = It
so I = Q/t
here Q = 4Q as for 1 disc
and f = f so t = 1/f so 4Q/1/f = 4Qf
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Oh I took g as 9.8114)
(0.35*3*9.81)+(0.1*1.4*9.81=(0.15*6*9.81)+ans
ans=2.8Nm
16)
80*28/100=112/5
112/5 =potential energy
112/5=mgh
112/5=(o.12)(9.81)h
P.Sonly 120 g taken into account as only the arrow has a movement.
17)
mgsinteta*speed=40% of total power mgsinteta=force
force*velocity=power
(total m)(9.81)sin30)==40%
100%=ans
18)
Show me your working, as its easy!
I actually don't get 18 work den=force x distance. Pressure = force|area so pressure x area x distance should be the work done right? That's pressure x volume but that much is given in all the choices
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http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w10_qp_12.pdf
Q5, 11, 22, 26 and 34. Please don't ignore this post at least XP
Q5, 11, 22, 26 and 34. Please don't ignore this post at least XP
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28)
Weight acts downwards so since it's in equilibrium the electric force has to act upwards. Since the plate up is positive and attracting the drop, that drop has to have a negative charge.
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5)
x is 0.44. Add uncertainties. U get 0.03. (0.03/0.44)*100 = 7%
11)
The tension in the rope needs to balance out the weight of the student acting downwards, so since the total tension needs to be opposite and equal to the weight, Let tension in rope on left side be T1 and the tension on rope on right side T2 and :. Total tension = T1sino + T2sino
add them up... W= 2Tsino, rearrange to get T= W/ 2sino. Answer: B
22)
because since k is low for the first spring, the box will prevent it from breaking by over extending. Hence A
26)
We know that distance between two minima is given by λ/2 (example, distance b/w T and S is λ/2)
We also know that Microwave travels with the speed of light c i.e is 3 * 10^8 m/s
Given distance b/w each minima is 15 mm so total distance from T to P would be 15 * 4 = 60 mm
Now distance b/w:
T and S = λ/2,
S and R = λ/2
R and Q = λ/2
Q and P = λ/2
and them you get 2λ
so 2λ = 60*10^-3
hence λ = 0.03 m
We know that c = f * λ
So f = c / λ
f = ( 3 * 10^8 ) / ( 0.03 )
f=10GHz
34)
voltage decreases linearly so its supposed to be B : as rho increases, there would be more steepness in graph
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hey can u help me with question 34 in this paper http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s11_qp_11.pdf
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17)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_12.pdf
q 17! please helppp its simple i know but i m not gettin it!
also q 18 22 25
thanx
At the bottom height is zero so mgh = zero
now going upwards..
2 block has height = 1 so mg1h
3 block = mg2h
4 block = mg3h
Sum up P.E ans is 6mgh
18)
efficiency = output power/input power
in this case its a generator so output power is P=VI = 230 x 32=7360
input power = E(potential) / time = Mgh/t = 200 x 8 x 9.81 = 15696
efficency = 7360/15696 x 100%=47% answer is D
22)
Basically, here they asked us to find volume of the crystal (cube), and then we are asked to find its length i.e is 3rd root of volume :¬
Find V from V = m / ρ and 3rd root (V) you'll get the answer
25)
IDK
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25: Wire of the same material so same Young Modulus and same load is also given.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_12.pdf
q 17! please helppp its simple i know but i m not gettin it!
also q 18 22 25
thanx
Extension is directly proportional to length and inversely to Area.
Half diameter so 1/4 Area and 1/4 length is given.
So extension will be same.
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Resistance=p*l/A
As all sides are same of a cube so R=p/l
L is cube root volume so Resistance is p/cube root V
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