- Messages
- 18
- Reaction score
- 42
- Points
- 23
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The weight is 0.15N and angle with the vertical is 30. Apply .15*tan30 to get the horizontal force.
1% of 2.00 is 0.02.Q4 pls
What exactly is the rate of flow of electrons and whats the formula invovled
Which question. ._. ?
what exactly is your question maybe I can help.generally, what is it? :S
In 14, why is it B why not A??14: Moment is calculated by force*distance so they are inversely proportional. B is the correct graph for this.
17 and 35
37. When resistance is zero, p.d. will be zero and current passing thorugh the circuit will be maximum due to low resistance.
When resistance is maximum, p.d. will be maximum but current will not be zero as some current passes through.
39. Few particles will bounce back as most of the mass is concentrated at a point so a head-on collision only will result in this which has a low probability.
Inversely proportional graphs are always like the one in B.In 14, why is it B why not A??
And using the method you mentioned in Qno. 35 please solve - http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf question 33
it doesnt seem to work
Thank you
C ?
http://www.allaboutcircuits.com/vol_1/chpt_1/7.htmlElectrons are negatively charged, and as such they will move from an area of lower potential to an area of higher potential. Also, they will move away from the negative terminal and towards the positive terminal (conventional current moves in the opposite direction, and in reality this flow of electrons is the current that actually transfers energy across the circuit).
Therefore, the current will go from the terminal on the right to the top-right corner of the circuit, move to the bottom right (point Y), move across the resistor to (point X) and then back to the positive terminal of the battery. Therefore, the current will be from Y to X (i.e. option C or D).
Furthermore, if the current is 4.8 Amperes, using the formula
Q = I * t
(Where Q is the charge that flows through a point in "t" seconds when a current of I Amperes is flowing)
we can say that
I = Q/t
So the current is equal to the rate of flow of charge past a point. Okay, so this has units Coulombs/Second, which is what we want (answer is also in same units).
So if the current is 4.8 Amperes, the rate of flow of charge is 4.8 Coulombs/Second.
How much is this? Let's see.
The charge on any 1 electron is 1.6 * 10⁻¹⁹ Coulombs. Therefore, to make up 1 Coulomb, we need 1/(1.6 * 10⁻¹⁹) = 6.25 * 10¹⁸ electrons.
But if 1 Coulomb is 6.25 * 10¹⁸ electrons per second, 4.8 Coulombs should be 4.8 * (6.25 * 10¹⁸) electrons per second, right?
Carrying out this calculation, we get 4.8 * (6.25 * 10¹⁸) = 30.0 * 10¹⁸ = 3.0 * 10¹⁹ electrons/second.
This flows in the direction of Y to X, therefore our answer must be A.
Hope this helped!
Good Luck for all your exams!
there are a series of formulae to apply in this one. you must make sense first.
density = mass/volume
he is moving up at rate of 50cm/s means 0.5m/s
if he is at constant speed there is no resultant force so all forces cancel out so
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