Q37 bhi pleaseLink ?
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Q37 bhi pleaseLink ?
15)Q37 bhi please
its B15)
Answer should be zero
Hadi Murtaza
ZaqZainab
19)
you need to find the power input... power = work done / time
work done = F x D or rather F here as Weight =mg = to find mass you use the formula density = mass/volume= 1000 x 340 = 340000... now converting it to weight x 9.8 = 3332000 ... Work done = 3332000 x distance (30 ) = 99960000
for power it has to be per second and youre given in the question per minute so you divide by 60s = 99960000/60 = 1666000 mnow thats the power in to find the power output you multiply bv the efficiency of the turbine generator = 1499400 = 1.5 MW
37)
-->After voltage passes through some resistance it will decrease
-->The higher the resistance the greater the decrease in voltage
-->So it will decrease less after passing through 2 ohm than when passing through 4 ohm
Why?its B![]()
(10*10^-2*2) =0.2for anti clockwiseWhy?
Take moments about pivotQ37 bhi please
Make a new convo b/w us...(10*10^-2*2) =0.2for anti clockwise
and clockwise (40*10^-2*4) =1.6 for clockwise
1.6-0.2=1.4
for finding the acceleration with lowest speed you have to divide no of protons with atomic mass
We apply the formula :¬http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_1.pdf
In question 20, why is the answer A isnt it the whole area of graph ie C ?
isnt work done the whole area under graph?We apply the formula :¬
1/2 * F * extension
so 1/2 * 25 * 0.2 = 2.5 J
well it depends on extensionisnt work done the whole area under graph?
Post the link of the question paper, it will be easier for others to answer.PLEASE HELP, MJ 2012, variant 13
qs:4,8,10,21,28,31,32,34
just 8qs please someone take the time to help me out and explain
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