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See its lengthy but easy...
All u shld know is that when the connection is in parallel, voltage division is the same for both..(here 2V in both)
Also resistors are equally distributed in the loops
let the left loop be called as A and the right loop as B(loop of the resistors)
For loop A, total of resist. is 15ohm and in other loop i.e. B is also 15ohm
But both of them are in parallel that why resistance of the circit as a whole is 15/2 (1/15+1/15=2/15 and its inverse)
using V=IR
2=I(15/2)
=> I=4/15
Dividing current equally, current in A is 2/15 and in B is 2/15
Now in a X is attached to end of 1 resistor, hence in A again using V=IR we getV=2/15*5=2/3
Now subtracting 2-2/3 gives 4/3 is the voltage at X
now, Y is attached to end of second resistor in loop B, hence, V at Y=2/15*10=4/3V
Subtracting 4/3 from 2 gives 2/3
Now V at X - Vat Y= 4/3-2/3 =2/3volts
