Physics: Post your doubts here!

[MaboroshI_I]

Can I get help with this question please?

 

[Rockstar RK]

yes

using V=IR
2=I(15/2)
=> I=4/15
Dividing current equally, current in A is 2/15 and in B is 2/15
Now in a X is attached to end of 1 resistor, hence in A again using V=IR we getV=2/15*5=2/3
Now subtracting 2-2/3 gives 4/3 is the voltage at X
now, Y is attached to end of second resistor in loop B, hence, V at Y=2/15*10=4/3
Subtracting 4/3 from 2 gives 2/3
Now V at X - Vat Y= 4/3-2/3 =2/3

 

[danial 234]

View attachment 45277
can someone solve it ive forgotten hw i did it bfore

120-80=40 kg
force=40*9.81
f=ma
find acc .. then use equation of motion to find speed when d=9metres

 

[danial 234]

Can I get help with this question please?

as R and 2R are in parallel .. so V2=V3
V=V1+V2 or V=V1+V3
V-V1=V3

 

[Rockstar RK]

Why did u divide lambda by 2???

It is because of the formula that distance between two adjacent maxima is lambda/2 and distance between minima and maxima is lambda/4

 

[Thought blocker]

I am glad, we all are capable of getting at least 35 of 40

 

[Rockstar RK]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_qp_1.pdf
Q36

See its lengthy but easy...
All u shld know is that when the connection is in parallel, voltage division is the same for both..(here 2V in both)
Also resistors are equally distributed in the loops
let the left loop be called as A and the right loop as B(loop of the resistors)
For loop A, total of resist. is 15ohm and in other loop i.e. B is also 15ohm
But both of them are in parallel that why resistance of the circit as a whole is 15/2 (1/15+1/15=2/15 and its inverse)
using V=IR
2=I(15/2)
=> I=4/15
Dividing current equally, current in A is 2/15 and in B is 2/15
Now in a X is attached to end of 1 resistor, hence in A again using V=IR we getV=2/15*5=2/3
Now subtracting 2-2/3 gives 4/3 is the voltage at X
now, Y is attached to end of second resistor in loop B, hence, V at Y=2/15*10=4/3V
Subtracting 4/3 from 2 gives 2/3
Now V at X - Vat Y= 4/3-2/3 =2/3volts

 

[ashcull14]

i gu

120-80=40 kg
force=40*9.81
f=ma
find acc .. then use equation of motion to find speed when d=9metres

ess i did the same bt the ans appears to b wrong C ..though its A

 

[Rockstar RK]

Come on guys and dolls just a bunch of hours left post ur doubts and get it solved

 

[Rockstar RK]

I am glad, we all are capable of getting at least 35 of 40

Attend this thread I will be back in an hour i have to go 4 dinner

 

[Thought blocker]

Attend this thread I will be back in an hour i have to go 4 dinner

bhaijaan!

 

[ashcull14]

Attend this thread I will be back in an hour i have to go 4 dinner

same ere

 

[umair1161]

View attachment 45277
can someone solve it ive forgotten hw i did it bfore

Can someone please explain this again... i still dont seem to get it :'(

 

[Thought blocker]

Can someone please explain this again... i still dont seem to get it :'(

Here :¬
Consider barrel :
Use F = ma
That is mg - T = ma (T = tension): 120g - T = 120a
Make T the subject of formula so, later we can equate it in other equation or you can solve it by simultaneous equation method also.
But I personally go for Equate so, T = 120g - 120a

Consider stake :
Again use F = ma
so T = 80g + 80a

Equate it to get acceleration :
120g-120a=80g+80a
a=0.5g

Now we use V² - U² = 2as
so V² = 2 x 0.5 (10) x 9
V = 6m/s

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_12.pdf
I need help with Q26, please!

Why sad ? You just don't know one part... but trust me... its easy
26)
As shown in the fig, at time = 18 s, phase diff btw the 2 waves = 180° or π.
1 wavelength = 360°
So, 1/8 of a wavelength = 360°/8 → 45°.

Phase diff = 180° at 18 s.
So, phase diff = 45° at x.
x = (18 * 45)/180
x = 4.5 s

Ans = B
Enjoy Physics

 

[ParulS]

June 2003
Q20
Can someone please solve and show ??

Thanks in advance

 

[Thought blocker]

June 2003
Q20
Can someone please solve and show ??

Thanks in advance

https://www.xtremepapers.com/community/attachments/image-jpg.44530/

 

[umair1161]

Here :¬
Consider barrel :
Use F = ma
That is mg - T = ma (T = tension): 120g - T = 120a
Make T the subject of formula so, later we can equate it in other equation or you can solve it by simultaneous equation method also.
But I personally go for Equate so, T = 120g - 120a

Consider stake :
Again use F = ma
so T = 80g + 80a

Equate it to get acceleration :
120g-120a=80g+80a
a=0.5g

Now we use V² - U² = 2as
so V² = 2 x 0.5 (10) x 9
V = 6m/s

uhh.... for: 120g-120a =80g + 80a

doesnt a=2 ??

because 200a= 40g

200a= 400 and therefore..... a=2 ??

please do correct me if im wrong though!

 

[omeraz]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s13_qp_12.pdf
Question 23 someone please help

 

[Thought blocker]

uhh.... for: 120g-120a =80g + 80a

doesnt a=2 ??

because 200a= 40g

200a= 400 and therefore..... a=2 ??

please do correct me if im wrong though!

Look i did a calculation mistake it should be a = 0.2g that is a = 2